All categories

3 years ago

In the figure shown below, if line m is parallel to line n, then find the value of x

Mathematics

1 answer:

Snezhnost [94]3 years ago

8 0

Answer:

Step-by-step explanation:

The two angles shown are considered "alternate interior angles" because they lie on the INSIDE of two parallel lines, but on alternate/opposite sides of the transversal line. Alternate interior angles are congruent. You can use transformations to see that they are congruent. Therefore, you should set the two expressions equal to each other and solve for x.

You might be interested in

4-14 Practice Problems

Kazeer [188]

Answer:

5 months

Step-by-step explanation:

Equation A: 15+30x

Equation B: 35x

In 5 months Gym a will cost 15+30(5) or $175 and Gym B will also cost $175.
Basically all you have to do is apply reasonable numbers until you find out where the costs will meet up.

6 0

2 years ago

The perimeter of a rectangle is

kondor19780726 [428]

<h3 /><h3> $verified \: answer \sqrt}$ </h3>

Equation for Perimeter of a rectangle: Perimeter = 2W + 2L

<h3>Defining the variables, let</h3>

<h3>Width = x</h3><h3>Length = 2x+3 (3 more than twice the width)</h3>

<h3>Plugging everything into the equation</h3>

<h3>30= 2(x) + 2(2x+3) using the distributive property,</h3>

<h3>30=2x+4x+6 combining like terms</h3>

<h3>30=6x+6 subtracting 6 from both sides,</h3>

<h3>24=6x divide both sides by 6</h3>

<h3>4=x This means that the width is 4 m.</h3>

<h3>To get the length, use the expression L=2x+3 and plug in x = 4 that was already solved for</h3>

<h3>So the dimensions of the rectangle are width is 4 m and length is 11 m.</h3>

8 0

3 years ago

Read 2 more answers

Find the area of each figure. round to the hundredths place when necessary

notsponge [240]

Answer:

115.48 $m^{2}$

Step-by-step explanation:

This shape can be split into two distinct shapes

Two halves of a semi circle, and a rectangle in between

Circle:

Putting both halves of the semi circle together will give you a full circle. The diameter of the circle is given (7m).

The area of a circle is A = π $r^{2}$

The radius, r, is half of the diameter, so 7 / 2 = 3.5m

A = π $r^{2}$

A = π * $3.5^{2}$

A = 38.38 $m^{2}$

Rectangle:

The area of a rectangle is A = h b

The height, h, is known at 7m

The base, b, can be found by removing the length from the dot to the end of the semi circles. This length is the radius of the semi circles, 3.5m

Removing the radius from the total length given

18 - 3.5 - 3.5 = 11m

The base is 11m

A = h b

A = 7 * 11 = 77 $m^{2}$

Total Area = Circle area + Rectangle area

Total Area = 38.38 + 77 = 115.48 $m^{2}$

6 0

3 years ago

A small can of tomato juice contains 56 mL of juice. A large can of tomato juice. A large can of tomato juice contains 202 mL of

Tomtit [17]

56 + 202 = 258 So your answer is 258

6 0

3 years ago

The population of a city in 2000 was 500,000 while the population of the suburbs of that city in 2000 was 700,000. Suppose that

Mnenie [13.5K]

Answer:

The population of the city in 2002 is 469,280 while the population of the suburb is 730,720.

Step-by-step explanation:

6% of the city's population moves to the suburbs (and 94% stays in the city).
2% of the suburban population moves to the city (and 98% remains in the suburbs).

The migration matrix is given as:

$A= \left \begin{array}{cc} \\ C \\S \end{array} \right\left[ \begin{array}{cc} C&S\\ 0.94&0.06 \\0.02&0.98 \end{array} \right]$

The population in the year 2000 (initial state) is given as:

$\left[ \begin{array}{cc} C&S\\ 500,000&700,000 \end{array} \right]$

Therefore, the population of the city and the suburb in 2002 (two years after) is:

$S_0A^2=\left \begin{array}{cc} [500,000&700,000]\\& \end{array} \right\left \begin{array}{cc} \end{array} \right\left[ \begin{array}{cc} 0.94&0.06 \\0.02&0.98 \end{array} \right]^2$

$A^{2} = \left[ \begin{array}{cc} 0.8848 & 0.1152 \\\\ 0.0384 & 0.9616 \end{array} \right]$

Therefore:

$S_0A^2=\left \begin{array}{cc} [500,000&700,000]\\& \end{array} \right\left \begin{array}{cc} \end{array} \right \left[ \begin{array}{cc} 0.8848 & 0.1152 \\ 0.0384 & 0.9616 \end{array} \right]\\\\=\left[ \begin{array}{cc} 500,000*0.8848+700,000*0.0384& 500,000*0.1152 +700,000*0.9616 \end{array} \right]\\\\=\left[ \begin{array}{cc} 469280& 730720 \end{array} \right]$

Therefore, the population of the city in 2002 is 469,280 while the population of the suburb is 730,720.

6 0

3 years ago