Answer:
12 dark chocolates
Step-by-step explanation:
Let there are 2x milk chocolates and 3x dark chocolates.
Total no of milk chocolates = 8
ATQ,
2x = 8
x = 4
Dark chocolates = 3x
= 3(4)
= 12
Hence, there are 12 dark chocolates.
Answer:
three or more
Step-by-step explanation:
Answer:
<h2>f(0) = -4</h2>
Step-by-step explanation:
![f(x)=4x^2+4x-4\ or\ f^*(x)=4x+4x-4=8x-4\\\\f(0)-\text{put}\ x=0\ \text{to}\ f(x):\\\\f(0)=4(0)^2+4(0)-4=4(0)+0-4=0-4=-4\\\\f^*(0)=8(0)-4=0-4=-4](https://tex.z-dn.net/?f=f%28x%29%3D4x%5E2%2B4x-4%5C%20or%5C%20f%5E%2A%28x%29%3D4x%2B4x-4%3D8x-4%5C%5C%5C%5Cf%280%29-%5Ctext%7Bput%7D%5C%20x%3D0%5C%20%5Ctext%7Bto%7D%5C%20f%28x%29%3A%5C%5C%5C%5Cf%280%29%3D4%280%29%5E2%2B4%280%29-4%3D4%280%29%2B0-4%3D0-4%3D-4%5C%5C%5C%5Cf%5E%2A%280%29%3D8%280%29-4%3D0-4%3D-4)
<span>S= (a+b)^2+(4a+b-2)^2+(9a+b-4)^2
98a+14b-44=0
14a+3b-6=0
a=24/49, b=-2/7
y = (24/49)x^2-(2/7)</span>