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MissTica
3 years ago
10

A rectangle has an area of 24 square units and a side length of 2 3/4 units. Find the other side length of the rectangle

Mathematics
1 answer:
Studentka2010 [4]3 years ago
4 0
Length is 12, Width 2, and Area is 24

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What is a No solution? What is a infinite solution?
galben [10]
No is a solid answer and infinite solution well that just means anything
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3 years ago
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What's the slope and intercept of y=4x-7
zalisa [80]

Answer:

the slope is 4 and the y-intercept is -7

Step-by-step explanation:

3 0
3 years ago
I'm doing Pre-algebra and I don't know how would I figure out the 13th term of the pattern; 100, 91, 82, 73.... without writing
Over [174]
The way we would answer the question would be to express it as

100-9(n-1) with n being the nth term of the pattern.

Why is this? We know we subtract 9 each time and START from 100.
Remember though that 100 is the first term in the sequence. So, we would have (n-1)*9 to subtract 0 from our 1st term and 9 from our second term.

Also, we have 9*(n-1) because we are just subtracting multiples of 9. It is always going to subtract by 9.


If you needed the answer here it is...

The answer to the problem would be 
100-9(13-1)
= 100-9(12)
= 100-108
= -8

5 0
3 years ago
Jason and Karina have matching gardens Jason plants 2/3 of his garden with roses Karina's garden is divided into ninths how much
olganol [36]

Answer:

6/9

Step-by-step explanation:

5 0
3 years ago
3. For the polynomial: ()=−2(+19)3(−14)(+3)2, do the following:A. Create a table of values that have the x-intercepts of p(x) in
Pepsi [2]

Part A. We are given the following polynomial:

\mleft(\mright)=-2\mleft(+19\mright)^3\mleft(-14\mright)\mleft(+3\mright)^2

This is a polynomial of the form:

p=k(x-a)^b(x-c)^d\ldots(x-e)^f

The x-intercepts are the numbers that make the polynomial zero, that is:

\begin{gathered} p=0 \\ (x-a)^b(x-c)^d\ldots(x-e)^f=0 \end{gathered}

The values of x are then found by setting each factor to zero:

\begin{gathered} (x-a)=0 \\ (x-c)=0 \\ \text{.} \\ \text{.} \\ (x-e)=0 \end{gathered}

Therefore, this values are:

\begin{gathered} x=a \\ x=c \\ \text{.} \\ \text{.} \\ x=e \end{gathered}

In this case, the x-intercepts are:

\begin{gathered} x=-19 \\ x=14 \\ x=-3 \end{gathered}

The multiplicity are the exponents of the factor where we got the x-intercept, therefore, the multiplicities are:

Part B. The degree of a polynomial is the sum of its multiplicities, therefore, the degree in this case is:

\begin{gathered} n=3+1+2 \\ n=6 \end{gathered}

To determine the end behavior of the polynomial we need to know the sign of the leading coefficient that is, the sign of the coefficient of the term with the highest power. In this case, the leading coefficient is -2, since the degree of the polynomial is an even number this means that both ends are down. If the leading coefficient were a positive number then both ends would go up. In the case that the leading coefficient was positive and the degree and odd number then the left end would be down and the right end would be up, and if the leading coefficient were a negative number and the degree an odd number then the left end would be up and the right end would be down.

Part C. A sketch of the graph is the following:

If the multiplicity is an odd number the graph will cross the x-axis at that x-intercept and if the multiplicity is an even number it will tangent to the x-axis at that x-intercept.

6 0
1 year ago
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