Answer:
13 quarters must be tails.
Step-by-step explanation:
Number of quarters = 40% of 50 coins
Number of quarters = 40/100 * 50 = 20 coins which are quarters.
35% of these 20 quarters on heads. We can proceed in 2 ways from here.
We can actually find the number of quarters that are on heads.
35/100 * 20 = 7 quarters are showing heads.
Since the other quarters must be tails 20 - 7 = 13 quarters must be tails.
The other way to do it is to realize that if 35% of the coins are heads, 65% of the coins must be tails 20 * 65/100 = 13 which is a bit more direct.
Answer:
Negative 35 divided by 5.
Step-by-step explanation:
I got this answer by using process of elimination. So let's try it shall we?
2+12
This has to positive numbers in the process of addition so this would be a positive number with the answer of 14.
-3 x -8
This equation has two negatives being multiplied by each other hence cancelling each other out so the answer would be positive.
10 - (-18)
Much like the last equation there are to negatives, but this equation is subtracting by a negative so the negatives next to each other in that way would cancel each other out leaving you with a positive 28.
-35 / 5
Seeing as we have checked every other equation this one must be negative but lets check. When you divide a negative by a positive the positive would automatically take the form of the negative number, because it does not have a negative of its own to cancel the negative out so this must have a negative outcome.
20 (4)^3-2
20(64)-2
1280-2
1278
To solve this, you re-arrange the equation to get
r by itself:
3r - 6 = 11q - 4
3r = 11q + 2 <span>(add 6 to both sides to cancel out the -6)
</span>r =
<span>(divide both sides by 3 to get what r is)
</span>
This can also be written as: r =
<span>-------------------------------------------------------------------------------------------------------------
</span>
ANSWER:
f(q) = 
<span>
OR
</span><span>
</span>
f(q) = 
OR
f(q) = (11q + 2) / 3 (if you can't put in fractions)
Answer:
Use the Pyth. Theorem
c being the Hypotenuse (x)
= 25
<em>Hope this helps!!!</em>
