All categories

2 years ago

If a = -8, b = -7, c = 6, then verify that (a+b) + c = a+ (b+c) tysm for de help ✨

Mathematics

1 answer:

NISA [10]2 years ago

5 0

The given information is,

→ a = -8

→ b = -7

→ c = 6

Let's verify the problem,

→ (a+b) + c = a+ (b+c)

→ (-8 - 7) + 6 = -8 + (-7 + 6)

→ -15 + 6 = -8 - 1

→ -9 = -9

→ [ LHS = RHS ]

Hence, it is equal and verified.

You might be interested in

Which equation has x = 4 as the solution?

Sindrei [870]

16=4 because in order to get 4 you need have to divide 16 into 4

5 0

3 years ago

Read 2 more answers

The dashed triangle is the image of the pre-image solid triangle.

BabaBlast [244]

The scale factor is 4.

6 0

3 years ago

Read 2 more answers

What is the volume of a sphere with a radius of 9 inches

Effectus [21]

Given the formula
V= $\frac{4}{3}$ πR³
so V= $\frac{4}{3}$ π9³=972π

7 0

3 years ago

Read 2 more answers

What is the solution to this equation? 4x^2+98=0

Bess [88]

There is no real solution

6 0

3 years ago

Assume the sample variances to be continuous measurements. Find the probability that a random sample of 25observations, from a n

konstantin123 [22]

Answer:

a) $P(4S^2 > 4*9.1) = P(\chi^2_{24} >36.4) = 0.0502$

b) $P(13.848$ Step-by-step explanation:

Previous concepts

The Chi Square distribution is the distribution of the sum of squared standard normal deviates .

For this case we assume that the sample variance is given by $S^2$ and we select a random sample of size n from a normal population with a population variance $\sigma^2$ . And we define the following statistic:

$T = \frac{(n-1) S^2}{\sigma^2}$

And the distribution for this statistic is $T \sim \chi^2_{n-1}$

For this case we know that n =25 and $\sigma^2 = 6$ so then our statistic would be given by:

$\chi^2 = \frac{(n-1)S^2}{\sigma^2}=\frac{24 S^2}{6}= 4S^2$

With 25-1 =24 degrees of freedom.

Solution to the problem

Part a

For this case we want this probability:

$P(S^2 > 9.1)$

And we can multiply the inequality by 4 on both sides and we got:

$P(4S^2 > 4*9.1) = P(\chi^2_{24} >36.4) = 0.0502$

And we can use the following excel code to find it: "=1-CHISQ.DIST(36.4,24,TRUE)"

Part b

For this case we want this probability:

$P(3.462 < S^2$

If we multiply the inequality by 4 on all the terms we got:

$P(3.462*4 < 4S^2 < 4*10.745)= P(13.848< \chi^2$ And we can find this probability like this: $P(13.848$ And we use the following code to find the answer in excel: "=CHISQ.DIST(42.98,24,TRUE)-CHISQ.DIST(13.848,24,TRUE)"

8 0

3 years ago