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just olya [345]
3 years ago
15

Helppppp plz 10points

Mathematics
1 answer:
Ivenika [448]3 years ago
4 0
I think it's answer B
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Please help me tysm :)
aivan3 [116]

Answer:

asdasd

Step-by-step explanation:

3 0
3 years ago
Read 2 more answers
Hi I need this question please asap.
Contact [7]
Ike Jehoshaphat isn’t oso los
6 0
3 years ago
The Kansas City Chiefs are trying to figure out if there is a relationship between the number of passes thrown by Quarterback Pa
stich3 [128]

The linear regression equation that represents this data is given as follows: y = 22x - 518.

Using this equation, when 38 passes are thrown, the expected yardage is of 318 yards.

<h3>How to find the equation of linear regression?</h3>

To find the regression equation, also called line of best fit or least squares regression equation, we need to insert the points (x,y) in the calculator. These points are given on a table or in a scatter plot in the problem.

In the context of this problem, the input and output are given as follows:

  • Input: number of passes thrown by Patrick Mahomes.
  • Output: number of passing yards obtaining by Mahomes/KC.

The points to be inserted in the calculator are given as follows:

(39, 360), (35, 235), (35, 262), (37, 249), (40, 338).

Hence the equation is given by:

y = 22x - 518.

With 38 passes, the expected yardage is calculated as follows:

y = 22(38) - 518 = 318 yards.

More can be learned about linear regression at brainly.com/question/22992800

#SPJ1

8 0
1 year ago
UPPER AND LOWER BOUNDS - PLEASE HELP!
Marianna [84]
Qn. 1
Lower bound for Zoe's weight = 62 - (1/2) = 62 - 0.5 = 61.5 kg

Qn. 2
Upper bound for length AB = 8.3+ (0.1/2) = 8.3+0.05 = 8.35 cm

Qn. 3
Upper bound for Anu's wight = 83+(0.5/2) = 83+0.25 = 83.25 kg

Qn. 4
Lower bound for length CD = 27-(0.5/2) = 27-0.25 = 26.75 cm

Qn. 5
Upper bound for sides of the hexagon = 3.6+(0.1/2) = 3.6+0.05 = 3.65 cm
Upper bound for the perimeter = upper bound for the sides*6 = 3.65*6 = 21.9 cm

Qn. 6
Perimeter = 4*length => side = Perimeter/4 = 24/4 = 6
Bound = 0.5/4 = 0.125
Lower bound of the length = 6-0.125 = 5.875 cm

Qn. 7
For the area,
Upper bound = 80+(10/2) 80+5 = 85 cm^2
For the length
Upper bound = 12+(1/2) = 12+0.5 = 12.5

Then, upper bound for the width = Upper bound for the area/upper bound for the length = 85/12.5 = 6.8 cm

Qn. 8
Lower bound for the area = 230-(1/2) = 230-0.5 = 229.5 cm^2
Lower bound for the sides of the square = Sqrt(Lower bound of the area) = Sqrt (229.5) = 15.15
Then,
Lower bound of perimeter = 4(Length) = 4*15.15 = 60.6 cm
8 0
3 years ago
Jordan volunteered for the same amount of time each day for 7 days. If he volunteered for 329 minutes altogether, how many minut
AVprozaik [17]

Answer:

47

Step-by-step explanation:

Just divide 329 by 7

That gives you 47

3 0
2 years ago
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