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user100 [1]
3 years ago
6

Triangle ABC is translated to image A′B′C′. In this translation, A(5, 1) maps to A′(6, –2). The coordinates of B′ are (–1, 0). W

hat are the coordinates of B? B( , )
Mathematics
2 answers:
Yakvenalex [24]3 years ago
8 0

Answer:

B' (-2, 3)

Step-by-step explanation:

A(5, 1)  to A'(6, -2)

A(6-5, -2-1)

A translation is 1, -3

consider the same translation of B'

therefore, the coordinates of B' is (-2, 3)

tatiyna3 years ago
5 0

Answer:

please mark my answer brainliest

Step-by-step explanation:

while solving this sum the main steps are...

make sure

area of 1st triangle =area of the new....tria..

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Therefore, n=6.
You can also figure this out if you know that 2^3*2^6=2^9. When you multiply exponents with the same base, add the exponents. 3+6=9

Final answer: n=6
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3 years ago
What is the geometric mean of 12 and 9
Ira Lisetskai [31]

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10.3923

Step-by-step explanation:

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8 0
3 years ago
Read 2 more answers
Apply the distributive propertyto create an equivalent expression. 1/2(6e-3f-3/4)
poizon [28]

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multiply each of the terms in the parenthesis by \frac{1}{2}

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= 3e - \frac{3}{2} f - \frac{3}{8}


8 0
3 years ago
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If g(x) = 5x2^2 - 10x + 9 and h(x) = -3x3^3+ 5x - 6, find g(x) - h(x)?
AnnZ [28]

Answer:

B)g(x) - h(x) =  3x^3 - 5x^2 - 15x + 15

Step-by-step explanation:

Here, the given functions are:

g(x) = 5x^2- 10x + 9 \\h(x) = -3x^3+ 5x - 6

Now, g(x) - h(x) is : 

(5x^2- 10x + 9)  - ( -3x^3+ 5x - 6)\\= 5x^2- 10x + 9 + 3x^3 - 5x + 6\\= 3x ^3 + 5x ^2+  (-10 x - 5 x) + (9 + 6)\\= 3x^3 - 5x^2 - 15x + 15

⇒(5x^2- 10x + 9)  - ( -3x^3+ 5x - 6) =  3x^3 - 5x^2 - 15x + 15

B) Hence, g(x) - h(x) =  3x^3 - 5x^2 - 15x + 15

3 0
3 years ago
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