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olya-2409 [2.1K]
3 years ago
10

What is the geometric mean of 12 and 9

Mathematics
2 answers:
Ira Lisetskai [31]3 years ago
8 0

Answer:

10.3923

Step-by-step explanation:

= ( 12 x 9 )^1/2

= ( 108 )^0.5

= 10.3923

PtichkaEL [24]3 years ago
4 0

Answer:

10.3923

Step-by-step explanation:

= ( 12 x 9 )0.5

= ( 108 )0.5

= 10.3923

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It takes 2 minutes to print 3 photos. AT this rate, how long does it take to print 10 photos?
sladkih [1.3K]

Answer:

15 photos

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6 0
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Please help I need help​
FinnZ [79.3K]

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its option 3;92667

Step-by-step explanation:

6 and 8 is 68 so 9 2667 its 92667

3 0
3 years ago
Solve the system of equations by finding the reduced row-echelon form of the augmented matrix for the system of equations.
ycow [4]

This  involves quite a lot of arithmetic to do manually.

The first thing you do is to make the first number in  row 2  = to 0.

This is done by R2 = -3/2 R1 + R2

so the matrix becomes

( 2        1          1)    ( -3 )

( 0    -13/2   3/2)   (1/2 )

(5       -1           2)  (-2)

Next step is to make  the 5 in row 5  = 0  

then  the -1  must become zero

You aim  for the form

( 1 0 0) (x)

(0 1 0) (y)

(0 0 1) ( z)

x , y and z will be the required solutions.


4 0
3 years ago
Read 2 more answers
Rewrite in simplest rational exponent form √x • 4√x. Show each step of your process.
Lisa [10]
First\ step:you\ must\ have\ the\ domain\ (D)\\x\geq0\to D:x\in[0;\ \infty)\\\\Second\ step:use\ \sqrt{a}\cdot\sqrt{a}=\left(\sqrt{a}\right)^2=a\ for\ a\geq0\\\\Solution:\\\sqrt{x}\cdot4\sqrt{x}=4(\sqrt{x})^2=\huge\boxed{4x}

or\ other\ method\\\\First\ step:\ use\ \sqrt{x}=x^{\frac{1}{2}}\\\\\sqrt{x}\cdot4\sqrt{x}=x^\frac{1}{2}\cdot4x^{\frac{1}{2}}\\\\Second\ step:\ use\ a^n\cdot a^m=a^{n+m}\\\\x^\frac{1}{2}\cdot4x^{\frac{1}{2}}=4\cdot x^\frac{1}{2}\cdot x^{\frac{1}{2}}=4x^{\frac{1}{2}+\frac{1}{2}}=4x^1=\huge\boxed{4x}
7 0
3 years ago
Evaluate the triple integral ∭ExydV where E is the solid tetrahedon with vertices (0,0,0),(5,0,0),(0,9,0),(0,0,4).
Elan Coil [88]

Answer: \int\limits^a_E {\int\limits^a_E {\int\limits^a_E {xy} } \, dV = 1087.5

Step-by-step explanation: To evaluate the triple integral, first an equation of a plane is needed, since the tetrahedon is a geometric form that occupies a 3 dimensional plane. The region of the integral is in the attachment.

An equation of a plane is found with a point and a normal vector. <u>Normal</u> <u>vector</u> is a perpendicular vector on the plane.

Given the points, determine the vectors:

P = (5,0,0); Q = (0,9,0); R = (0,0,4)

vector PQ = (5,0,0) - (0,9,0) = (5,-9,0)

vector QR = (0,9,0) - (0,0,4) = (0,9,-4)

Knowing that cross product of two vectors will be perpendicular to these vectors, you can use the cross product as normal vector:

n = PQ × QR = \left[\begin{array}{ccc}i&j&k\\5&-9&0\\0&9&-4\end{array}\right]\left[\begin{array}{ccc}i&j\\5&-9\\0&9\end{array}\right]

n = 36i + 0j + 45k - (0k + 0i - 20j)

n = 36i + 20j + 45k

Equation of a plane is generally given by:

a(x-x_{0}) + b(y-y_{0}) + c(z-z_{0}) = 0

Then, replacing with point P and normal vector n:

36(x-5) + 20(y-0) + 45(z-0) = 0

The equation is: 36x + 20y + 45z - 180 = 0

Second, in evaluating the triple integral, set limits:

In terms of z:

z = \frac{180-36x-20y}{45}

When z = 0:

y = 9 + \frac{-9x}{5}

When z=0 and y=0:

x = 5

Then, triple integral is:

\int\limits^5_0 {\int\limits {\int\ {xy} \, dz } \, dy } \, dx

Calculating:

\int\limits^5_0 {\int\limits {\int\ {xyz}  \, dy } \, dx

\int\limits^5_0 {\int\limits {\int\ {xy(\frac{180-36x-20y}{45} - 0 )}  \, dy } \, dx

\frac{1}{45} \int\limits^5_0 {\int\ {180xy-36x^{2}y-20xy^{2}}  \, dy } \, dx

\frac{1}{45} \int\limits^5_0  {90xy^{2}-18x^{2}y^{2}-\frac{20}{3} xy^{3} } \, dx

\frac{1}{45} \int\limits^5_0  {2430x-1458x^{2}+\frac{94770}{125} x^{3}-\frac{23490}{375}x^{4}  } \, dx

\frac{1}{45} [30375-60750+118462.5-39150]

\int\limits^5_0 {\int\limits {\int\ {xyz}  \, dy } \, dx = 1087.5

<u>The volume of the tetrahedon is 1087.5 cubic units.</u>

3 0
3 years ago
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