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Kazeer [188]
4 years ago
7

Find a power series representation for the function. (Assume a > 0.) (Give your power series representation centered at x = 0

.) f(x) = x3 a6 − x6
Mathematics
1 answer:
vova2212 [387]4 years ago
3 0

Answer:

Power series representation of given f(x) is \sum^{\infty}_{n=0}(-1)^{n}(\frac{x^{6n+3}}{a^{6n+6}})

Step-by-step explanation:

Given that:

                    f(x)=\frac{x^{3}}{a^{6}-x^{6}} --- (1)

writing it in form f(x)=\frac{1}{1-x} for which power series is:

                    \frac{1}{1-x}=\sum^{\infty}_{n=0}(-1)^{n}x^{n}---(2)

                    f(x)=\frac{x^{3}}{a^{6}}\frac{1}{1-\frac{x^{6}}{a^{6}}} --- (3)

consider:

                    u=\frac{x^{6}}{a^{6}}

substituting above eq. in (3)

                    f(x)=\frac{x^{3}}{a^{6}}\frac{1}{1-u}

Expanding\frac{1}{1-u} using (2)

                    =\frac{x^{3}}{a^{6}}\sum^{\infty}_{n=0}(-1)^{n}u^{n}

Back-substituting value of u in above

                   =\frac{x^{3}}{a^{6}}\sum^{\infty}_{n=0}(-1)^{n}(\frac{x^{6}}{a^{6}})^{n}\\=\sum^{\infty}_{n=0}(-1)^{n}(\frac{x^{6n+3}}{a^{6n+6}})

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