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Furkat [3]
3 years ago
9

Question 4 of 10

Mathematics
1 answer:
ludmilkaskok [199]3 years ago
5 0

Answer:

Option C. 3√3

Step-by-step explanation:

Please see attached photo for brief explanation.

In the attached photo, we obtained the following:

Opposite = a

Adjacent = 3

Hypothenus = 6

Angle θ = 60°

We can obtain the value of 'a' as follow:

Tan θ = Opposite /Adjacent

Tan 60° = a/3

Cross multiply

a = 3 x Tan 60°

But: Tan 60° = √3

a = 3 x Tan 60°

a = 3 x √3

a = 3√3

Therefore, the length of the altitude of the equilateral triangle is 3√3.

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icang [17]

Answer:

y=(x^2 -2x-3)/3

Step-by-step explanation:

f(x)= √3x+4 -1

x=√3y+4 -1

(x+1)^2=(√3y+4)^2

3y+4=x^2 +2x+1

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4 0
3 years ago
Solve. 5 < x – 2 < 11
lions [1.4K]
The answer is 7 < x < 13.

5 < x - 2 < 11
Add 2 in all sections:
5 + 2 < x - 2 + 2 < 11 + 2
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3 years ago
Find two unit vectors orthogonal to both given vectors. i j k, 4i k
Maurinko [17]
The cross product of two vectors gives a third vector \mathbf v that is orthogonal to the first two.

\mathbf v=(\vec i+\vec j+\vec k)\times(4\,\vec i+\vec k)=\begin{vmatrix}\vec i&\vec j&\vec k\\1&1&1\\4&0&1\end{vmatrix}=\vec i+3\,\vec j-4\,\vec k

Normalize this vector by dividing it by its norm:

\dfrac{\mathbf v}{\|\mathbf v\|}=\dfrac{\vec i+3\,\vec j-4\,\vec k}{\sqrt{1^2+3^2+(-4)^2}}=\dfrac1{\sqrt{26}}(\vec i+3\,\vec j-4\vec k)

To get another vector orthogonal to the first two, you can just change the sign and use -\mathbf v.
6 0
3 years ago
Answer please and explain
Fiesta28 [93]

Answer:

C=84

Step-by-step explanation:

Since you use 3 for pi. You plug the radius into the formula. C=2×3x14=84

5 0
3 years ago
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