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3 years ago

What is 2xy-3yz+5+2yz-xy

Mathematics

1 answer:

melomori [17]3 years ago

6 0

To simplify this expression, we are going to combine like terms.

First, we can see that we have two terms with the variables $xy$ being multiplied together, $2xy$ and $-xy$ . Together, these add to $xy$ , so our expression is now:

$xy - 3yz + 5 + 2yz$

We also have two terms with $yz$ , $-3yz$ and $2yz$ . Together, these add to $-yz$ , so our expression is now:

$xy - yz + 5$

Our final expression is xy - yz + 5.

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Two line are ___ if and only if they lie in the same plane and do not intersect, and two lines are __ if and only if they lie in

Vilka [71]

the answer is C, I think because parallel lines never touch

6 0

3 years ago

Proportional relationships, please answer all of the parts! Thank you!

Natalka [10]

Answer:

a. No (see below)

b. (see below)

c. Johnny

d. Johnny = $12.50 / hour Doug = $9.16... / hour

e. Doug: extend the table to show how much he gets paid for 1 hour of work (the unit rate)

Johnny: already on the graph

Step-by-step explanation:

a. No. This is because a proportional relationship would have a certain ratio between payment and the amount of time spent working, which would not change. However, if Doug's neighbour pays him $55 for 6 hours, it's likely that this is not a proportional relationship, or we would be able to divide $55 by the 6 hours Doug spent working.

b. Even though above I said that it's probably not a proportional relationship, if it were, we would have to divide everything equally. I'm guessing the table should look like this:

Doug

Time (hr) Earnings ($)

4 $36.66...

5 $45.8333...

6 $55

7 $64.4666....

8 $73.333...

To work out how much Doug would get for working 4 hours:

4/6 x $55 = 2/3 x $55 = $36.66... (so definitely not a proportional relationship)

To work out how much Doug would get for working 5 hours:

5/6 x $55 = $45.8333.... (more evidence that this is not a proportional relationship)

To work out how much Doug would get for working 7 hours (we already got 6 hours):

7/6 x $55 = $64.4666...

To work out how much Doug would get for working 8 hours:

8/6 x $55 = $73.33... (we could double the 4 hour payment, but this is probably more accurate)

c. Johnny is getting paid more. If we look at how much Doug gets for 6 hours, it's $55. If we look out at how much Johnny gets for 6 hours, it's $75. (If we do the same with the other amounts of time, it's the same.

4 hours: D = $36.67 vs J = $50

5 hours: D = $45.83 VS J = $60

etc...

d. Johnny gets $75 per 6 hours --> 75/6 = $12.50 per hour

Doug gets $55 per 6 hours --> 55/6 = $9.1666... per hour

e. Carry on the table for Doug all the way to 1, so you can see the how much Doug gets paid for 1 hour of work (i.e. the minimum).

The unit rate is already on the graph for Johnny.

HOPE THIS HELPED :)

P.S. Mate cld you please give me Brainliest? That table took so much dam work

7 0

4 years ago

Read 2 more answers

Matthew walks 5/8 to the bus stop each morning. How far will he walk in 5 days?

fomenos

5 points not 10 but 5/8 each day 5 days=5 times 5/8=5/1 times 5/8=25/8=24/8+1/8=3+1/8=3 and 1/8 3 and 1/8 mile

8 0

3 years ago

Help? don't know what to pick, and please dont choose randomly

Yakvenalex [24]

Answer:

yess!!!

step-by-step explained.

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3 years ago

Read 2 more answers

I need some help with math

Irina18 [472]

Answer:

$(y-7)^2+(x-2)^2=16$

and

$(x+2)^2+(y-15)^2 = 9$

Step-by-step explanation:

The standard equation of a circle is $(x-h)^2+(y-k)^2=r^2$ where the coordinate (h,k) is the center of the circle.

Second Problem:

We can start with the second problem which uses this info very easily.
(h,k) in this problem is (-2,15) simply plug these into the equation. $(x--2)^2+(y-15)^2=r^2$ .
We can also add the radius 3 and square it so it becomes 9. The equation.
This simplifies to $(x+2)^2+(y-15)^2 = 9$ .

First Problem:

The first problem takes a different approach it is not in standard form. But we can convert it to standard form by completing the square.
$y^2-14y+x^2-4x+37=0$ first subtract 37 from both sides so the equation is now $y^2-14y+x^2-4x=-37$ .
$y^2-14y+x^2-4x+37=0$ by adding $(-\frac{b}{2a} )^2$ to both the x and y portions of this equation you can complete the squares. $(-\frac{b}{2a})^2=(-\frac{-14}{2(1)})^2$ and $(-\frac{-4}{2(1)})^2$ which equals 49 and 4.
Add 49 and 4 to both sides and the equation is now: $y^2-14y+49+x^2-4x+4=-37+49+4$ You can simplify the y and x portions of the equations into the perfect squares or factored form $(y-7)^2$ and $(x-2)^2$ .
Finally put the whole thing together. $(y-7)^2+(x-2)^2=16$ .

I hope this helps!

5 0

3 years ago