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2 years ago

Pls help me anyone I don’t get this pls

Mathematics

1 answer:

Setler [38]2 years ago

4 0

Answer:

1. Y=-2x+3

2. Y=3x+2/3

I'm sorry I can't get them all but I know these are right

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Help on this question

Lostsunrise [7]

start with elimination. 8 x 8 is only 64 so C and D dont make sense. The are of the circle is pi(r)². so the radius is 4 squared then multiply by pi and devide by 5 to get the 5 equal parts. So B 10.

3 0

3 years ago

Helpp plz i'll mark brainliest (see picture). The second part is, What is the value of y?

Art [367]

Answer:

116*

Step-by-step explanation:

36* + 28* = 64*

180* - 64* = 116*

4 0

3 years ago

Find the quotient. -245 - 35 a. -7 b. - 5 C. 5 d 7

DanielleElmas [232]

a. -7 is your answer dear.

Step-by-step explanation:

Ur complete Question is like -245/35 = -7

3 0

2 years ago

Read 2 more answers

A spherical balloon is being inflated at a rate of 3 cubic inches per second. Determine the change in the rate of the radius.How

Novay_Z [31]

Answer:

The rate rate of change of radius is $\frac{1}{48\pi}$ inches per second when the diameter is 12 inches.

The radius is changing more rapidly when the diameter is 12 inches.

Step-by-step explanation:

Consider the provided information.

A spherical balloon is being inflated at a rate of 3 cubic inches per second.

The volume of sphere is $V=\frac{4}{3}\pi r^3$

Differentiate the above formula with respect to time.

$\frac{dV}{dt}=4\pi r^2\frac{dr}{dt}$

Substitute the respective values in the above formula,

$3=4\pi 6^2\frac{dr}{dt}$

$\frac{1}{48\pi}=\frac{dr}{dt}$

The rate rate of change of radius is $\frac{1}{48\pi}$ inches per second when the diameter is 12 inches.

When d=16

$3=4\pi 8^2\frac{dr}{dt}$

$\frac{3}{256\pi}=\frac{dr}{dt}$

Thus, the radius is changing more rapidly when the diameter is 12 inches.

5 0

3 years ago

Need help with this data table need it to end up to 1024 thanks

Iteru [2.4K]

1 2 4 8 16 32 64 128 256 512 1024. each one is 2 times the previous

3 0

3 years ago