Collections are used to store, retrieve, manipulate, and communicate aggregate data.
Answer:
Starting from root, recursively traverse the min-heap. Once we find a key with value less than our X, we know that every key in subtree of that key will be also smaller than our X. Otherwise, we should keep traversing.
Explanation:
The complexity of this algorithm will be O(N) where N is the number of keys in our min-heap.
Answer:
vec[0].push_back(10)
Explanation:
Given
Declaration: vector <int> vec
Required
Assign 10 to the first element
This can be done using the push_back keyword.
The syntax is: <em>vectorname[position].push_back(value); </em>
In this case:
vectorname = vec
position = 0 i.e. first element
value = 10
So, we have:
vec[0].push_back(10)
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