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mafiozo [28]
3 years ago
12

What number is between 2/7 and 4/11 CHECK MY ANSWER PLEASE?!?!

Mathematics
1 answer:
-BARSIC- [3]3 years ago
3 0
Yes, that's correct. All you do is add the two numbers together and then divide by 2!
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Find tan 0.<br> (Marking brainliest if correct) <br><br> 8/17<br> 15/17<br> 15/8<br> 8/15
Rina8888 [55]

Answer:

15/8

Step-by-step explanation:

Assuming you mean tan theta

Tan(theta) = opposite/adjacent

We know the adjacent side is 8 so the bottom of the fraction must also be 8

C: 15/8 is the only option that fits this criteria

4 0
2 years ago
(x-2)times (x^2+8x-1)
DerKrebs [107]

Answer:

x^3+6x^2-17x+2

Step-by-step explanation:

(x-2)*(x^2+8x-1)

=x(x^2+8x-1)-2(x^2+8x-1)

=x^3+8x^2-x-2x^2-16x+2

collect like terms

= x^3+6x^2-17x+2

6 0
3 years ago
A random number generator is used to select a number from 1 to 100 what is the probability of selecting number 151
topjm [15]
0.

It is impossible for 151 to be selected, as it is outside the range of numbers (1 to 100) that can be selected. Therefore the probability is 0.
4 0
3 years ago
Marine fuel is a combination of gasoline and motor oil. The standard gasoline and oil mixture is about 98% gasoline and about 2%
Georgia [21]

Answer:

0.98g+ 0.02m= 7.1224 gallons standard mixture

0.96g+ 0.04m= 6.25 gallons break oil

3.92 gallons of gasoline  is required for  4 gallons the standard mixture

Step-by-step explanation:

If we have to use 6 gallons of gasoline this means that 98%= 6 gallons and 2% would be 6/98*2

Gasoline: Motor oil

6              :    x

98        : 2

Using the product rule

x= 6*2/98= 0.1224 gallons of motor oil is required.

Let the gasoline be represented by g and motor oil by m then for the standard oil the equation would be

0.98g+ 0.02m= 7.1224 gallons standard mixture

For break in oil

Gasoline: Motor oil

6              :    x

96        : 4

Using the product rule

x= 6*4/96= 0.25 gallons of motor oil is required.

Let the gasoline be represented by g and motor oil by m then for the break oil the equation would be

0.96g+ 0.04m= 6.25 gallons break oil

Part b. For  4 gallons of the "break in" mixture

96% of the 4 gallons of the "break in" mixture is gasoline =  3.84 gallons of gasoline

4% of 4 = 0.16 gallons of motor oil

Now the standard mixture 4 gallons would contain 98 % of gasoline and 2 % of motor oil

98% of 4 gallons= 3.92 gallons of gasoline

2% of  4 gallons= 0.08 gallons of motor oil.

6 0
2 years ago
Write a rule that represents the function (0,0)(1,0.5)(2,2)(3,4.5)(4,8)
kirza4 [7]
The rule that represents those numbers is .....idk
6 0
2 years ago
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