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2 years ago

Convert 0.00049 to scientific notation.

Mathematics

1 answer:

Step2247 [10]2 years ago

6 0

4.9 x 10 to the power of -4

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Assume that you want to test the claim that the paired sample data come from a population for which the mean difference is μd =

swat32

Answer:

Test statistic, $t_{s} = -0.603$ (to 3 dp)

Step-by-step explanation:

Deviation, d = x -y

Sample mean for the deviation

$\bar{d} = \frac{\sum x-y}{n}$

$\bar{d} = \frac{(28-6) + (31-27)+(20-26)+(25-25)+(28-29)+(27-32)+(33-33)+(35-34)}{8} \\\bar{d} = -0.625$

Standard deviation: $SD = \sqrt{\frac{\sum d^{2} - n \bar{d}^2}{n-1} }$

$\sum d^{2} = (28-26)^2 + (31-27)^2 +(20-26)^2 +(25-25)^2 +(28-29)^2 +(27-32)^2 +(33-33)^2 +(35-34)^2\\\sum d^{2} = 63$

$SD = \sqrt{\frac{63 - 8 * (-0.625)^2}{8-1} }$

SD =2.93

Under the null hypothesis, the formula for the test statistics will be given by:

$t_{s} = \frac{ \bar{d}}{s_{d}/\sqrt{n} } \\t_{s} = \frac{- 0.625}{2.93/\sqrt{8} }$

$t_{s} = -0.6033$

6 0

2 years ago

Tyrel is dividing 4 by 15. If he continues the process, what will keep repeating in the quotient?

kobusy [5.1K]

Answer:

i think b

Step-by-step explanation:

4 0

2 years ago

Can you help please?

harkovskaia [24]

Step-by-step explanation:

Mechanical advantage can be defined using distances:

Mechanical advantage = input distance / output distance

Or it can be defined using forces:

Mechanical advantage = output force / input force

Solving for the output force:

Output force = mechanical advantage × input force

Plugging in values:

Output force = 2.2 × 202 N

Output force = 444.4 N

3 0

2 years ago

If x = 0 and y < 0, where is the point (x, y) located?

Ulleksa [173]

It’s 0 hope this helps(:

4 0

2 years ago

What is the range of the function y = -x2 + 1?

meriva

<span><span>y = 2 + 2sec(2x) The upper part of the range will be when the secant has the smallest positive value up to infinity. The smallest positive value of the secant is 1 So the minimum of the upper part of the range of y = 2 + 2sec(2x) is 2 + 2(1) = 2 + 2 = 4 So the upper part of the range is [4, ) The lower part of the range will be from negative infinity up to when the secant has the largest negative value. The largest negative value of the secant is -1 So the maximum of the lower part of the range of y = 2 + 2sec(2x) is 2 + 2(-1) = 2 - 2 = 0 So the lower part of the range is (, 0]. Therefore the range is (, 0] U [4, ) </span>
</span>

3 0

3 years ago