Answer:
a. Slope is -2/7
b. b = 1
c. y = 2x + 1
Hope this helps :)
Step-by-step explanation:
The whole idea of that kind of graph is that they allow you to view the complete distribution of data while also being able to see first and third quartiles, the median, and the minimums and maximums.
One pound is 16oz. So you take 54 and minus it by 16 until you get something less that 16. Then you take how many times you subtracted it, and that is how many pounds. Then you take the "leftover" number and they you have your answer.
so Sarita used 3 pounds and 8 oz.
To solve this problem, we must imagine the triangles and
parallel lines which are formed. It is best to draw the triangle described in
the problem so that you can clearly understand what I will be talking about.
The first step we have to do is to make an equality equation
in triangle ABC.
In triangle ABC, we are given that lines XY and BC are two
parallel lines (XY || BC). Therefore
this means that:
AX / XB = AY / YC --->
1
The next step is to make an equality equation in triangle
AXC.
We are given that lines ZY and XC are two parallel lines (ZY
|| XC). Therefore this also means that:
AZ / ZX = AY / YC ---> 2
Combining 1 and 2 since they have both AY / YC in common:
AX / XB = AZ / ZX
we are given that:
AZ = 8, ZX = 4 therefore AX = AZ + ZX = 12, hence
12 / XB = 8 / 4
XB = 6
Answer:
1.98 × 10^10
Step-by-step explanation:
First solve for how many text messages were sent out per one month:
22,000,000 × 900
19,800,000,000
Convert into scientific notation:
1.98 × 10^10
In scientific notation, there can only be one number before the decimal. The rest of the numbers must be after the decimal; hence, why I put the numbers 9 and 8 after the decimal. If the rest of the numbers are zeros, you do not have to add them after the decimal. Instead, starting from right to left, count the number places until you reach your decimal. The number you have counted will be your exponent. I counted nine 0's, one 8, and one 9 which made this exponent 10 as there were 10 decimal placements.
