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Fed [463]
2 years ago
6

Help! giving brainlest thx!

Mathematics
2 answers:
leonid [27]2 years ago
7 0

Answer:

The first answer is the last one and the other is the third

Step-by-step explanation:

the the first one is in obtuse because this wider than 90° and the other one is shorter than 90°

kipiarov [429]2 years ago
6 0

Answer:

The first one is an Obtuse triangle and the second is an Acute isosceles triangle :)

Step-by-step explanation:

Hope this helped!

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Find the area of this shape
cestrela7 [59]

Answer:

28ft^2

Step-by-step explanation:

you only need 2 things to find the area of the triangle, base and height. The formula for finding the area is 1/2(base x height)

if we plug the numbers we are given into the formula we find

1/2(7x8)

1/2(56)

28

we find that the area of this triangle is 28ft^2

6 0
3 years ago
GUYS CAN ANYONE HELP ME WITH 5 and 6 please
Karolina [17]

Answer:

first one is 120cm

second one is 7.5 miles

Step-by-step explanation:

one book is 3.75

maximum books are 25

so 25×3.75 = 93.75

second question he crosses 0.63 to go for work

and 0.63 to go home so in one day he crosses 1.26 miles

in 6 days is (1.26×6) = 7.56

3 0
3 years ago
What is the area of a rectangle with vertices at ​ (0, −4) ​, ​ (−1, −3) ​ , (2, 0) , and (3, −1) ? Enter your answer in the box
Bad White [126]

We are given vertices of a rectangle (0, −4) ​, ​ (−1, −3) ​ , (2, 0) , and (3, −1).

Length is the distance between (0, −4) ​and ​ (−1, −3) points.

Width is distance between  (−1, −3) ​ and (2, 0) points.

<u>Computing length:</u>

\mathrm{Compute\:the\:distance\:between\:}\left(x_1,\:y_1\right),\:\left(x_2,\:y_2\right):\quad \sqrt{\left(x_2-x_1\right)^2+\left(y_2-y_1\right)^2}

=\sqrt{\left(-1-0\right)^2+\left(-3-\left(-4\right)\right)^2}

=\sqrt{2}

<u>Computing Width :</u>

\mathrm{The\:distance\:between\:}\left(-1,\:-3\right)\mathrm{\:and\:}\left(2,\:0\right)\mathrm{\:is\:}

=\sqrt{\left(2-\left(-1\right)\right)^2+\left(0-\left(-3\right)\right)^2}

=3\sqrt{2}

<h3>Area of the rectangle = Length × Width  </h3>

= \sqrt{2} \times 3\sqrt{2} = 3 \times 2 = 6 \ squares \ units..


7 0
3 years ago
Please help need this answer
I am Lyosha [343]

A function is a relation for which each value from the set the first components of the ordered pairs is associated with exactly one value from the set of second components of the ordered pair.

(2, 0), (-3, 3), (9, 1), (-3, 5)  NOT

(9, 1), (-3, 4), (2, 1), (9, 2)     NOT

(2, 4), (-3, 2), (9, 1), (-7, 2)     YES

(2, 4), (-3, 6), (2, 3), (-7, 2)     NOT

8 0
3 years ago
I need help with this problem
sertanlavr [38]

Answer:

Step-by-step explanation:

ill help

6 0
3 years ago
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