What are the solutions of 3(x-4)(2x-3)=0 check all that apply
2 answers:
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When you arrange the N points in sequence around the polygon (clockwise or counterclockwise), the area is half the magnitude of the sum of the determinants of the points taken pairwise. The N determinants will also include the one involving the last point and the first one.
For example, consider the vertices of a triangle: (1,1), (2,3), (3,-1). Its area can be computed as
(1/2)*|(1*3-1*2) +(2*-1-3*3) +(3*1-(-1)*1)|
= (1/2)*|1 -11 +4| = 3
For example, consider the vertices of a triangle: (1,1), (2,3), (3,-1). Its area can be computed as
(1/2)*|(1*3-1*2) +(2*-1-3*3) +(3*1-(-1)*1)|
= (1/2)*|1 -11 +4| = 3
Answer:
<h2>A = 36π yd² ≈ 113.04 yd²</h2><h2>C = 12π yd ≈ 37.68 yd</h2>Step-by-step explanation:
The formula of an area of a circle:
The formula of a circumference of a circle:
<em>r</em><em> - radius</em>
<em />
We have <em>r = 6yd</em>.
Substitute:
If you want round the answers, then use <em>π ≈ 3.14</em>
Answer:
a.) f(x) = -⅙(x+3)²+6
Step-by-step explanation:
The maximum value, our vertex, is at point (-3,6).
We can insert this value into the vertex form of a quadratic function and then solve for a as follows...
a equals -1/6... We can input this into the original equation we used...
f(x) = -1/6(x+3)^2+6
Good luck on the bellwork ;)