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ICE Princess25 [194]
4 years ago
8

sqrt{45}" align="absmiddle" class="latex-formula">
Mathematics
1 answer:
FinnZ [79.3K]4 years ago
4 0

Answer:

\sqrt{3} + \sqrt{15}

Step-by-step explanation:

\sqrt{(\sqrt{3}+\sqrt{15})^{2} }

\sqrt{3} + \sqrt{15}

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a surveyor measures the distance to the two landmarks as shown in the diagram what is the distance d. between the landmarks​
Inessa [10]
<h3>The distance between two landmarks is 123 meters</h3>

<em><u>Solution:</u></em>

We have to find the distance between two landmarks

<em><u>Use the law of cosines</u></em>

The third side of a triangle can be found when we know two sides and the angle between them

c^2 = a^2 + b^2 - 2ab\ cos c

Here, angle between 90 meters and 130 meters is 65 degrees

From figure,

a = 90

b = 130

c = d

Therefore,

d^2 = 90^2 + 130^2 - 2(90)(130)\ cos 65\\\\d^2 = 8100 + 16900 - 23400\ cos\ 65\\\\d^2 = 25000 - 23400 \times 0.4226\\\\d^2 = 25000 - 9889.267\\\\d^2 = 15110.73\\\\d = 122.92\\\\d \approx 123

Thus, the distance between two landmarks is 123 meters

8 0
3 years ago
How do I write a expression for the sequence in the table? Answer fasts plzz
photoshop1234 [79]

Answer:

the answer for number 1 is 18

the answer for number 2 is 14

the answer for number 3 is 50

4 0
3 years ago
What is the position of b on the number line below
Readme [11.4K]
I can’t seem to see the line below
8 0
3 years ago
A random number generator app on your phone generates two numbers between 0 and 8. What is the probability that the first number
aev [14]

Answer:

1/27

Step-by-step explanation:

There are 9 numbers between 0 and 8.  3 of them are less than 3 (0, 1, and 2), and 1 of them is 6.

The probability is therefore (3/9) (1/9) = 1/27.

8 0
3 years ago
In the figure below, segment CD is parallel to segment EF and point H bisects segment DE :
Grace [21]

Answer:

See explanation

Step-by-step explanation:

In the figure below, segment CD is parallel to segment EF, DE is a transversal, then angles DIH and HGI are congruent as alternate interior angles when two parallel lines are cut by a transversal.

Consider triangles DIH and EGH. In these triangles,

  • \angle DIH\cong \angle EGH as alternate interior angles;
  • \angle DHI\cong \angle GHE as vertical angles;
  • DH\cong HE because point H bisects segment DE (given).

Thus,

\triangle DIH\cong \triangle EGH by AAS postulate

4 0
3 years ago
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