We are given the function <span>f(x) = 3^x+1 - 2 and is asked for the asymptote and y-intercept. In this case, we transform the function to
y +2 = 1/3^(x+1)-1
y = 1-2</span>/3^(x+1)-1/(3^(x+1)-1)
let 3^(x+1)-1 = 0
<span>1/3^(x+1) = 0
x = infinity
when x = infinity
y = 0 - 2
y = -2
The y-intercept is the value where x = 0. substituting,
y = 3^(0+1) - 2 = 1 </span>
Answer:
x - y = -9
3x + 3y = 8
Step-by-step explanation:
Let the first number be x
Let the second number be y
Equation 1:
x - y = -9
Equation 2:
3x + 2y = 8
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Answer:
Question 39: False
Question 43: True
Step-by-step explanation:
<u>Question 39</u>
|-4| is a solution of x ≤ 4
|-4| ⇒ This mean the absolute value of 4. The sign s are neglected.
So, |-4| is not a solution of x ≤ 4.
<u>Question 43</u>
The point (5, -1) is a solution of the equation: y = 2x − 11.
To prove this we are to substitute the point (5, -1) in the equation y = 2x − 11.
y = -1 and x = 5
y = 2x − 11 ⇒ -1 = 2(5) -11
-1 = 10 - 11
-1 = -1
This is your generic run-of-the-mill sinusoidal function:
f(x) = sin(x)
This is the same sine function but with a phase shift of 3 units to the right:
f(x) = sin(x-3)
This is the sine function but with an amplitude of 4 units:
f(x) = 4sin(x)
This is the sine function but flipped across the x-axis:
f(x) = -sin(x)
Combine all these transformations to get:
f(x) = -4sin(x-3)
Answer:
1
Step-by-step explanation:
note that i = , thus
i² = ( )² = - 1
= i² × i² = - 1 × - 1 = 1