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larisa [96]
3 years ago
9

The National School Scrabble Tournament takes 264 minutes. There are 6 rounds in the tournament of equal time. How long is 1 rou

nd.
1. 258 minutes
2. 132 minutes
3. 44 minutes
4. 24 minutes
Mathematics
1 answer:
trapecia [35]3 years ago
7 0
44 minutes (264<span>÷6=44)

</span>
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They look correct to me!
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2x - 4<br> 5<br> = 4<br> What does x equal
marysya [2.9K]

Answer:

x=20, please confirm as problem layout is incorrect.

Step-by-step explanation:

I’m going to assume that this means 2/5x-4=4

You get 2/5x=8

X=20

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The Spix’s Macaw eats seeds, plants, fruits, and flowers. One of these birds ate the same amount of seeds each day for 5 days. O
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Answer:

13 seeds for day 1, 2, 3, 4, and 5.

Step-by-step explanation:

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3 years ago
The 12 boys in the class make up 15% of the class. What is the total number of students in the class?
alina1380 [7]

Answer:

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5 0
3 years ago
The diagram shows a circle inside a semicircle.
rjkz [21]

A circle inside a semicircle is depicted in the diagram. The circle measures 10 cm in diameter. The semicircle has a 20 cm diameter. Calculate the shaded area. Give a precise response to the nearest decimal point.

The area of the shaded region is 39.3cm^{2}.

Given the diagram shows a circle inside a semicircle.

Every point in the plane of a circle, which is a closed, two-dimensional object, is evenly separated from the center. All lines that cross the circle join together to produce the line of reflection symmetry. Every angle also possesses rotational symmetry about its center.

Area of a circle = \pi r^{2}.

Semicircle is when a line travelling through the center of a circle reaches its two ends, a semicircle is created. Thus, a circle can be formed by combining two semicircles.

Area of a semicircle = \frac{1}{2} \pi r^{2}.

The circle has a diameter of 10 cm. The semicircle has a diameter of 20 cm.

Semicircle:

r_{1}=\frac{d_{1} }{2}=\frac{20}{2}=10cm\\S_{1}=\frac{ \pi r_{1}^{2}  }{2}   =\frac{ \pi \times 10^{2}  }{2} =50\pi cm^{2}

Circle:

r_{2}=\frac{d_{2} }{2}=\frac{10}{2}=5cm\\S_{2}=\pi r_{2}^{2}   = \pi \times 5^{2}  =25\pi cm^{2}

So,

S=\frac{S_{1} -S_{2}}{2} \\S=\frac{50\pi -25\pi}{2}\\S=\frac{25\pi}{2} \\S=39.3cm^{2}

Therefore, The area of the shaded region is 39.3cm^{2}.

To learn more about semicircle visit: brainly.com/question/3442660

#SPJ1

8 0
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