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Papessa [141]
3 years ago
13

A ferris wheel is 32 meters in diameter and makes one revolution every 4 minutes. for how many minutes of any revolution will yo

ur seat be above 24 meters?
Mathematics
1 answer:
Licemer1 [7]3 years ago
5 0
4m = 32
1m = 8
x > 24
x > 3m
x = 4m
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√x+4=√3x <br><br> A.) x=2<br> B.) x=-2<br> C.) x=3<br> D.) x=-3
Agata [3.3K]
I hope this helps you

6 0
3 years ago
Read 2 more answers
Danny brought a car for £10000 the value of the car depreciated by 20% in the first year then the value of the car depreciated b
Levart [38]

£7200

In first year depreciates by 20%, that is it is worth 80% of it's original value

80% = \frac{80}{100} = 0.8

value after 1 year = 0.8 × £10000 = £8000

In the second year it depreciates by 10% of it's value, that is it is worth 90% of it's value at the end of the first year.

90% = \frac{90}{100} = 0.9

value after 2 years = 0.9 × £8000 = £7200


6 0
3 years ago
Write a problem involving how much more Than and solve it. Explain how drawing a diagram helped you solve the problem
avanturin [10]
A very simple example problem to satisfy the required above is,
"John has 8 apples and 17 oranges. How much more oranges does John has than apple?"

To answer this item, one needs to subtract the number of apples from the number of oranges. This is as shown below,
     D = 17 - 8 = 9

The concept of "how much more than" is linked to finding the difference between the numbers. 
6 0
3 years ago
Show your work<br><br> 7(x-8)=2x-31
victus00 [196]

Answer:

x=5

Step-by-step explanation:

7 (x-8)=2x-31

Distribute the 7 to the x and -8 (basically multiple 7 with the x and -8)

7x-56=2x -31

Drag the 2x over to the other subtracting it from 7x.

7x-2x-56=-31

5x-56=-31

Drag the 56 to the other side and add it to -31

5x= -31+56 (or 56-31)

5x= 25

Divide 5x from 25 to get your X

x=25/5

x=5

Hope this helps!!

3 0
3 years ago
2x² - 5x+1 has roots alpha and beta. Find alpha⁴+beta⁴ without solving the equation.
shepuryov [24]

Answer:

Step-by-step explanation:

\alpha+\beta=\dfrac{5}{2} \\\\\alpha*\beta=\dfrac{1}{2} \\\\\alpha^2+\beta^2=\dfrac{21}{4} \ (see\ previous\ post)\\\\(\alpha+\beta)^4=\dfrac{625}{16} \\\\=\alpha^4+\beta^4+4*\alpha^3*\beta+6*\alpha^2*\beta^2+4*\alpha*\beta^3\\\\=\alpha^4+\beta^4+4*(\alpha*\beta)(\alpha^2+\beta^2)+6*\alpha^2*\beta^2\\\\\alpha^4+\beta^4=(\alpha+\beta)^4-4*(\alpha*\beta)(\alpha^2+\beta^2)-6*\alpha^2*\beta^2\\\\= \dfrac{625}{16} -4*\dfrac{1}{2} *\dfrac{21}{4} -6*(\dfrac{1}{2})^2 \\\\

= \dfrac{625}{16}- \dfrac{168}{16}-\dfrac{24}{16}\\\\\\= \dfrac{433}{16}

7 0
3 years ago
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