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zimovet [89]
2 years ago
10

75% letter size paper and 25% legal size paper. What is the ratio of letter size paper to legal size paper

Mathematics
1 answer:
ruslelena [56]2 years ago
3 0

Answer:

3:1

Step-by-step explanation:

75%=\frac{75}{100}=\frac{3}{4}

25%=\frac{25}{100}=\frac{1}{4}

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antiseptic1488 [7]

here's the coordinates

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1 year ago
Need help with math
podryga [215]

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2 years ago
In an arithmetic sequence, = 5 and = 11.
Free_Kalibri [48]

Answer:

1134.62 (THE SUM OF 20 TERMS)

Step-by-step explanation:

First we write out our given information:

a8=2a2

a11=18

an is an arithmetic sequence.

Where here an means the nth term of our sequence.

What does an arithmetic sequence mean? It means to get to the next term in your sequence you add a constant (c) each time:

an+1=an+c

Equivalently:

an+1−an(n+1)−n=c

So an is of slope c (c2 is another constant):

an=cn+c2

Where here c2=a0 (Substitute in n=0 and see why that has to be the case if we let a0 exist)

Now we use the other given information to try to come up with a solution.

Let n=2:

a2=2c+c2

Let n=8, using the above equation we have:

a8=8c+c2=2a2=4c+2c2

Let n=11

a11=18

a11=11c+c2

But a11−a8=(11c+c2)−(8c+c2)=3c

Hence, a11=3c+a8

a11=3c+4c+2c2=18

a11=3c+8c+c2=18

5 0
2 years ago
Find the midpoint of the line segment whose endpoints are the given points. (-24.6, 38.1) and (-25.7, -17.7)
CaHeK987 [17]

Answer:

Midpoint is(-25.15,10.2)

Step-by-step explanation:

A line segment refers to line that has two endpoints.

Let (a,b),(c,d) be the endpoints of a line segment.

Midpoint of the line segment is given by (\frac{a+c}{2} ,\frac{b+d}{2})

Take the given points as follows:

(a,b)=(-24.6,38.1)\\(c,d)=(-25.7,-17.7)

Midpoint of a line segment =(\frac{-24.6-25.7}{2},\frac{28.1-17.7}{2})

=(\frac{-50.3}{2} ,\frac{20.4}{2} )\\=(-25.15,10.2)

7 0
2 years ago
There are 560 students at Smith Middle School, 45% of them are in athletics. How many students are in athletics?
zzz [600]

Answer:

252

Step-by-step explanation:

560x0.45 is 252

6 0
2 years ago
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