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devlian [24]
3 years ago
14

jack has $7.55 of change in his pocket. if he has 4 more dimes than than nickels, and twice as many quarters as nickels, how man

y of each coin does jack have
Mathematics
1 answer:
dolphi86 [110]3 years ago
8 0

Answer:

11 nickels, 15 dimes, 22 quarters

Step-by-step explanation:

number of nickels = x

number of dimes = x+4

number of quarters = 2x

- - - - - -

total of nickels = 5x cents

total of dimes = 10x + 40 cents

total of quarters = 50x cents

- - - - - -

755 = 5x + 10x + 40 + 50x

755 = 65x + 40

715 = 65x

x = 11

x+4 = 15

2x = 22

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Anna35 [415]

First divide both sides by 5. Then you get the answer. -0 or 0 I'm not sure tho


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3 years ago
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Solve for w.<br> 40+4w=12w
Xelga [282]

Answer:

W=5

Step-by-step explanation:

40+4w=12w

-4w -4w

40= 8w

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5=w

7 0
3 years ago
Greg throws a snowball hitting Kyle 3 out of 5 throws. If Greg makes 60 throws, how many times does he hit Kyle?
evablogger [386]
36 throws because you divide 60 by five and get 12 and then multiply 3 by 12 giving you 36, are you sure this is high school 
3 0
3 years ago
The path of a roller coaster over a particular length of track can be represented by a quadratic function f, where f(x) represen
alexgriva [62]
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If you were to graph this function, you would find that the zeros (x-intercepts) of the function are at the points of -2 and 1. Those are the needed points in the problem.

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8 0
3 years ago
After a rotation of 90° about the origin, the coordinates of the vertices of the image of a triangle are A'(6, 3), B'(-2, 1),
Rasek [7]

Answer:

<em>A</em>(-3, 6), <em>B</em>(-1, -2), <em>C</em>(-7, 1)

Step-by-step explanation:

To the pre-image after a 270°-counterclockwise rotation [90°-clockwise rotation], just reverse it by doing a 270°-clockwise rotation [90°-counterclockwise rotation]:

Extended Rotation Rules

  • 270°-clockwise rotation [90°-counterclockwise rotation] >> (x, y) → (-y, x)
  • 270°-counterclockwise rotation [90°-clockwise rotation] >> (x, y) → (y, -x)
  • 180°-rotation >> (x, y) → (-x, -y)

So, perform your rotation:

270°-clockwise rotation [90°-counterclockwise rotation] → <em>C</em><em>'</em>[1, 7] was originally at <em>C</em>[-7, 1]

→ <em>B'</em>[-2, 1] was originally at <em>B</em>[-1, -2]

→ <em>A</em><em>'</em>[6, 3] was originally at <em>A</em>[-3, 6]

I am joyous to assist you anytime.

3 0
3 years ago
Read 2 more answers
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