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Damm [24]
3 years ago
10

Pls help me solve for x in 2/3=x/4+x/3

Mathematics
1 answer:
Firlakuza [10]3 years ago
7 0

Answer:

x=8/7

Step-by-step explanation:

2/3=x/4+x/3

3x/12+4x/12=8/12

7x/12=8/12

x=(8/12)/(7/12)

x=(8/12)(12/7)

x=8/7

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the perimeter of a scalene triangle is 14.5 cm. the longest side is twice that of the shortest side. which equation can be used
madreJ [45]
Let a = longest side      <em> (Establishing labels)</em>
let b = shortest side
let c = third side

P = 14.5                <em>     (Given)</em>
a = 6.2
b = 1/2(a)

P = a + b + c
P = 6.2 + 3.1 + c        <em>(Fill in given info in equation)</em>

P = 9.3 + c                <em>(Simplify)</em>

14.5 = 9.3 + c           <em>(Simplify)</em>

c = 14.5 - 9.3           <em>(Solve)</em>
c = 5.2

Hope this made sense!
5 0
3 years ago
Read 2 more answers
IF YOU HELP I'LL MARK AS BRAINLIEST
11111nata11111 [884]

Answer:

A is reflected over the y axis and translated 2 units up and 2 units to the right.

Translate is the math word for slide

7 0
3 years ago
Read 2 more answers
Please help! I've been working on this for a few days and I just don't understand, it's due in a few hours. Thank you.
never [62]

Answer:

Part A: α = arc tan (y/x) = tan⁻¹ (y/x)

Part B: quadrant II α = arc tan (- y/x) = arc (- tan (y/x)) = - tan⁻¹ (y/x) 180°>α>90°

            quadrant III α = arc tan (-y)/(-x) = arc tan (y/x) = tan⁻¹ (y/x) 270°>α>180°

            quadrant IV α = arc tan (- y/x) = arc (- tan (y/x)) = - tan⁻¹ (y/x) 360°>α>270°

Part C: quadrant II 180°>α>90°  α = tan⁻¹ (-6/1) = - tan⁻¹ 6 = 180° - 80.53° = 99.47°

Step-by-step explanation:

PART A:

In this case we will use trigonometric function tanα to calculate angle α:

tanα = y/x => α = arc tan (y/x) = tan⁻¹ (y/x)

This formula is use in general way and in first quadrant  90°>α>0°

Part B:

But in the other quadrants you must know to use unit circle to reduce angle from II, III and IV quadrant to the first quadrant.

If angle is in the quadrant II  180°>α>90° then

tanα = - tan (180°-α)

If angle is in the quadrant III  270°>α>180° then

tanα = tan (α-180°)

If angle is in the quadrant IV  360°>α>270° then

tanα =- tan (360°-α)

Part C:

vector w (x,y) = (-1,6) this vector lies in quadrant II      180°>α>90°

180°- α = tan⁻¹ (-6/1) = - tan⁻¹ 6 = 80.53°  => 180° - α = 80.53°

α = 180° - 80.53 = 99.47°

It's not easy to understand this, but it's not easy for me to explain.

God with you!!!

5 0
2 years ago
Order these numbers from least to greatest.<br> 6.09, 6.009, 6.5071, 6.5
Savatey [412]

Answer:

6.009,6.09,6.5,6.5071

Step-by-step explanation:

3 0
3 years ago
Solve for x. <br><br> 6x + 2 = 14
oksian1 [2.3K]
6x + 2 - 2 = 14 - 2
6x/6 = 12/6
x = 2
8 0
3 years ago
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