I'll assume that's an exponent at the end there:
The first derivative gives the velocity. The second derivative gives the acceleration; increasing velocity is the same as positive acceleration. So we want to find when the second derivative is positive.
Let's see if we can use to avoid multiplying this out.
That worked; let's do it again:
That's a nice parabola. It's zero or negative for so positive everywhere else:
Answer: Increasing velocity when t < 1 or t > 3
length = 3234 m and width = 1614 m
let the width = w then length = 2w + 6
Perimeter = 2 ( length + width )
= 2 (2w + 6 + w ) = 2 ( 3w + 6 ) = 6w + 12
given perimeter = 9696 the equating gives
6w + 12 = 9696
subtract 12 from both sides
6w = 9696 - 12 = 9684
divide both sides by 6
w = = 1614
width = 1614 m and length = (2 × 1614 ) + 6 = 3234 m
Alright, lets get started.
At the beginning of her training, she is able to run 2 miles without stopping means 2 will be in the addition when we will write the equation for her running miles.
Her goal is to increase her distance by three quarters of a mile each week.
Means in first week, she will add the distance = miles
Suppose she runs x weeks, so shee will add distance =
So, suppose she runs total number of miles = d, then
Where d is total numer of miles she runs
x is number of weeks : Answer
Hope it will help :)