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3 years ago

8

Evaluate each expression. Show step by step 5(4-1)

2 answers:

djverab [1.8K]3 years ago

5 0

Answer:

15

Step-by-step explanation:

5x4=20

5x-1=-5

20-5=15

levacccp [35]3 years ago

5 0

Answer:

15

Step-by-step explanation:subtract 4-1 which is 3 and then you multiply 5x3 and it equals 15

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Simplify xz³ × 4x⁴z⁵

Inessa [10]

Answer:

4x⁵z8

Step-by-step explanation:

7 0

3 years ago

Help me with my math quiz from friday 4/1 <br> SHOW STEPS

malfutka [58]

Hie!! I will be solving the questions in the sequence of the attachments.

_______________________________________

4. As line SU and TV are intersecting each other at O.

A.T.Q, ∠UOV = (7x - 4)°

∠SOT = 87°

Then, ∠UOV = ∠SOT {Vertically Opposite Angles}

$\rightarrow\sf{7x - 4=87}$

$\rightarrow\sf{7x =87+4}$

$\rightarrow\sf{7x =91}$

$\rightarrow\sf{x =\frac{91}{7}}$

$\rightarrow\boxed{\bf{x =13}}$

_______________________________________

5. radius = 17ft

circumference of circle = 2πr

$\rightarrow\sf{circumference=2\times\frac{22}{7}\times17}$

$\rightarrow\boxed{\bf{circumference=106.8ft}}$

_______________________________________

3. ∠1 and ∠2 - add to 180 (linear pair)

∠1 and ∠3 - equal (Vertically Opposite Angles)

∠3 and ∠4 - add to 180 (linear pair)

∠2 and ∠4 - equal (Vertically Opposite Angles)

_______________________________________

2. 160° + (6x - 16)° = 180° (linear pair)

$\rightarrow\sf{6x - 16 = 180-160}$

$\rightarrow\sf{6x - 16 = 20}$

$\rightarrow\sf{6x = 20+16}$

$\rightarrow\sf{6x =36}$

$\rightarrow\sf{x =\frac{36}{6}}$

$\rightarrow\boxed{\bf{x =6}}$

8 0

2 years ago

In a Science class students made rockets out of empty 2-liter bottles. When launched, Karen's rocket reached a height of 12 and

velikii [3]

13 9/10

This is just a math equation. Just add 12 1/2 to 1 2/5 and remember that the bottoms of fractions have to be the same and if you change the bottoms, you have to change the top just as much :)

8 0

3 years ago

Read 2 more answers

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AnnyKZ [126]

HOLY THATS ALOT OF POINTS OMGUdjdjdbxbfkdnn

6 0

3 years ago

Read 2 more answers

The set of points (-3, 4), (-1, 1), (-3,-2), and (-5,1) identifies the vertices of a quadrilateral. Which is the most specific d

KIM [24]

Answer:

Option (4). Rhombus

Step-by-step explanation:

From the figure attached,

Distance AB = $\sqrt{(x_{2}-x_{1})^2+(y_{2}-y_{1})^2}$

= $\sqrt{(1-4)^2+(-5+3)^2}$

= $\sqrt{(-3)^2+(-2)^2}$

= $\sqrt{13}$

Distance BC = $\sqrt{(4-1)^2+(-3+1)^2}$

= $\sqrt{9+4}$

= $\sqrt{13}$

Distance CD = $\sqrt{(-2-1)^2+(-3+1)^2}$

= $\sqrt{9+4}$

= $\sqrt{13}$

Distance AD = $\sqrt{(1+2)^2+(-5+3)^2}$

= $\sqrt{9+4}$

= $\sqrt{13}$

Slope of AB ( $m_{1}$ ) = $\frac{y_{2}-y_{1}}{x_{2}-x_{1}}$

= $\frac{4-1}{-3+5}$

= $\frac{3}{2}$

Slope of BC ( $m_{2}$ ) = $\frac{4-1}{-3+1}$

= $-\frac{3}{2}$

If AB and BC are perpendicular then,

$m_{1}\times m_{2}=-1$

But it's not true.

[ $m_{1}\times m_{2}=(\frac{3}{2})(-\frac{3}{2})$ = - $\frac{9}{4}$ ]

It shows that the consecutive sides of the quadrilateral are not perpendicular.

Therefore, ABCD is neither square nor a rectangle.

Slope of diagonal BD = $\frac{4+2}{-3+3}$

= Not defined (parallel to y-axis)

Slope of diagonal AC = $\frac{1-1}{-1+5}$

= 0 [parallel to x-axis]

Therefore, both the diagonals AC and BD will be perpendicular.

And the quadrilateral formed by the given points will be a rhombus.

5 0

3 years ago