Answer:
4x⁵z8
Step-by-step explanation:
Hie!! I will be solving the questions in the sequence of the attachments.
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4. As line SU and TV are intersecting each other at O.
A.T.Q, ∠UOV = (7x - 4)°
∠SOT = 87°
Then, ∠UOV = ∠SOT {Vertically Opposite Angles}





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5. radius = 17ft
circumference of circle = 2πr


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3. ∠1 and ∠2 - add to 180 (linear pair)
∠1 and ∠3 - equal (Vertically Opposite Angles)
∠3 and ∠4 - add to 180 (linear pair)
∠2 and ∠4 - equal (Vertically Opposite Angles)
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2. 160° + (6x - 16)° = 180° (linear pair)






13 9/10
This is just a math equation. Just add 12 1/2 to 1 2/5 and remember that the bottoms of fractions have to be the same and if you change the bottoms, you have to change the top just as much :)
HOLY THATS ALOT OF POINTS OMGUdjdjdbxbfkdnn
Answer:
Option (4). Rhombus
Step-by-step explanation:
From the figure attached,
Distance AB = 
= 
= 
= 
Distance BC = 
= 
= 
Distance CD = 
= 
= 
Distance AD = 
= 
= 
Slope of AB (
) = 
= 
= 
Slope of BC (
) = 
= 
If AB and BC are perpendicular then,

But it's not true.
[
= -
]
It shows that the consecutive sides of the quadrilateral are not perpendicular.
Therefore, ABCD is neither square nor a rectangle.
Slope of diagonal BD =
= Not defined (parallel to y-axis)
Slope of diagonal AC =
= 0 [parallel to x-axis]
Therefore, both the diagonals AC and BD will be perpendicular.
And the quadrilateral formed by the given points will be a rhombus.