Question

Point P is at (3,-3) it undergoes the transformation (x - 2, y + 3). Where is P' at?​

Answer 1

Answer:

The coordinates of P' are $P'(x,y) = (1, 0)$.

Step-by-step explanation:

The coordinates of the point P' is determined by the following expression:

$P'(x, y) = P(x,y) + T(x,y)$ (1)

Where:

$P(x,y)$ - Original point.

$P'(x,y)$ - Translated point.

$T(x,y)$ - Translation vector.

If we know that $P(x,y) = (3, -3)$ and $T(x,y) = (-2, 3)$, then the coordinates of point P':

$P'(x,y) = (3, -3) + (-2, 3)$

$P'(x,y) = (1, 0)$

The coordinates of P' are $P'(x,y) = (1, 0)$.