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Goshia [24]
3 years ago
5

Point P is at (3,-3) it undergoes the transformation (x - 2, y + 3). Where is P' at?​

Mathematics
1 answer:
Vanyuwa [196]3 years ago
5 0

Answer:

The coordinates of P' are P'(x,y) = (1, 0).

Step-by-step explanation:

The coordinates of the point P' is determined by the following expression:

P'(x, y) = P(x,y) + T(x,y) (1)

Where:

P(x,y) - Original point.

P'(x,y) - Translated point.

T(x,y) - Translation vector.

If we know that P(x,y) = (3, -3) and T(x,y) = (-2, 3), then the coordinates of point P':

P'(x,y) = (3, -3) + (-2, 3)

P'(x,y) = (1, 0)

The coordinates of P' are P'(x,y) = (1, 0).

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Find Radius :
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Base area = πr²
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