Answer:
Let's analyze the possible sums of both dices, i will use the notation:
Dice1 + Dice 2 = sum.
also remember that we have 2 dices, with 6 options each.
So the total number of combinations is 6*6 = 36
we have 36 possible outcomes.
I will start at the extremes, the minimum that we can sum is 2, and the maximum is 12, then:
We can have 2 if:
1 + 1 = 2
only one permutation.
and 12 if:
6 + 6 = 12
Again, only one permutation.
so 2 and 12 have the same chance (1 out of 36)
now, to have 3 we can have:
2 + 1 = 3
or
1 + 2 = 3.
and to have 11
5 + 6 = 11
6 + 5 = 11
Again, 3 and 11 have the same probability (2 out of 36 options)
And now we can see a pattern.
4 and 10 will have the same chance.
5 and 9 will have the same chance
6 and 8 will have the same chance
7 is the only number that has an unique chance (and it has the largest one)
