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Stolb23 [73]
3 years ago
5

Jasper made a flag for his football team.He painted 1/2 of the flag blue and 1/2 of the flag yellow.He added stars to 1/3 of the

blue section.What fraction of the total flag is the blue section with stars?
Mathematics
2 answers:
Sindrei [870]3 years ago
8 0
Multiply 1/2 by 1/3 to get 1/6
lozanna [386]3 years ago
4 0
1/2 of the flag is blue and now another 1/3 is. 1/2 + 1/3 = 5/6, hope this helps
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A composite figure is shown.
VikaD [51]

The surface area of the pyramid is 60 square feet

The surface area of the square prism is 480 square feet

The surface area of the cube is 180 square feet

The total surface area is 720 square feet

<h3>Area of Composite figures</h3>

From the question, we are to calculate the surface area of each part of the composite figure

  • For the cube

Surface area of a cube is given by

S = 6l^{2}

Where l is the length of a side

But only have 5 surfaces of the cube are part of the composite figure

∴ Surface area of the cubic part of the figure = 5l^{2}

From the given information,

l = 6 \ feet

∴ Surface area of the cubic part of the figure = 5 × 6²

Surface area of the cubic part of the figure= 180 square feet

  • For the square prism

The surface area of a square prism is given by the formula,

S = 2l^{2} + 4lh

Where l is the length of the sides and

h is the height

But the <u>square surfaces</u> are not part of the surface of the figure

∴ Surface area of the square prism in the figure = 2l^{2} + 4lh -  2l^{2}

Surface area of the square prism in the figure = 4lh

From the given information,

l = 6 \ feet

h = 20 \ feet

Thus,

Surface area of the square prism part of the figure = 4×6×20

Surface area of the square prism part of the figure = 480 square feet

  • For the pyramid

The pyramid is a square pyramid

The surface area of a square pyramid is given by

S = l^{2} + 2l\sqrt{\frac{l^{2} }{4}+h ^{2} }

Where l is the base length

and h is the height of the prism

But the <u>square base</u> is not part of the surface of the figure

∴ Surface area of the pyramid part of the figure = l^{2} + 2l\sqrt{\frac{l^{2} }{4}+h^{2}  }\  - ( l^{2})

Surface area of the pyramid part of the figure = 2l\sqrt{\frac{l^{2} }{4}+h^{2}  }

From the given information,

l = 6 \ feet

h = 4 \ feet

∴ Surface area of the pyramid part of the figure = 2(6)\sqrt{\frac{6^{2} }{4}+4^{2}  }

= 12\sqrt{\frac{36 }{4}+16}

= 12\sqrt{9+16 }

= 12\sqrt{25}

= 12 × 5

= 60 square feet

Hence, the surface area of the pyramid is 60 square feet

Thus,

The total surface area = 180 square feet + 480 square feet + 60 square feet

The total surface area = 720 square feet

Hence, the total surface area is 720 square feet

Learn more on Calculating area of composite figures here: brainly.com/question/13175744

#SPJ1

4 0
2 years ago
The expression 4x/5-2x/3 is equivalent to?
shutvik [7]

Answer: The answer B

Step-by-step explanation: so the answer i got was x 5 so its B

7 0
3 years ago
What is 34,569,072 rounded to the nearest million
strojnjashka [21]
For this, look at the 6th digit (hundred-thousands). If that digit is more than or equal to 5, then the next digit is rounded up. Since it is, the answer becomes 35,000,000.
Answer: 35,000,000
4 0
3 years ago
Read 2 more answers
Find the reference angle for 105 degree angle.
m_a_m_a [10]

Answer:

75° degree angle

Step-by-step explanation:

Since the angle 105° is in the second quadrant, subtract 105° from 180° .

180-105=75

6 0
3 years ago
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Help!!! Find the center and radius of the circle with the equation (x-4)²+(y+6)²=16
WITCHER [35]

Answer:

Center:  (4,-6)

Radius: 4

Step-by-step explanation:

It is necessary to remember that the Equation of the circle in Center-radius form, is:

(x -h)^2 + (y-k)^2 = r^2

Where the center of the circle is at the point (h, k) and the radius is "r".

Then, given the following equation of the circle:

(x-4)^2+(y+6)^2=16

We can notice that it is written in Center-radius form. Then we can identify that:

h=4\\k=-6

Therefore the center is:

(4,-6)

And the radius is:

r^2=16\\\\r=\sqrt{16}\\\\r=4

5 0
3 years ago
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