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anzhelika [568]
3 years ago
13

What properties of a figure are preserved under a rotation?

Mathematics
1 answer:
Mekhanik [1.2K]3 years ago
3 0
Isometries I'm guessing<span>

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The length of a rectangle is 3 m longer than its width. if the perimeter of the rectangle is 38 m , find its area.
Gwar [14]
2l • 2w= 38
w+3=l


15•2+4•2=38
4+3=15. xxx

11•2+8•2=38
8+3=11. ✓✓✓✓✓✓✓


a=11•8
a=88
6 0
3 years ago
1+4v&lt;9 can you guys help me?
Elena L [17]

Answer:

v < 2

Step-by-step explanation:

1+4v<9

Subtract 1 from each side

1-1+4v<9-1

4v < 8

Divide each side by 4

4v/4 <8/4

v < 2

4 0
3 years ago
Solve the equation (2y-6)(y+3)=0
Leokris [45]
See the picture below

6 0
3 years ago
Read 2 more answers
What is 45 * 89 + 67 &lt;55 - 56 =
gladu [14]

Answer:

False

Step-by-step explanation:

Use the order of operations

45 * 89 = 4005

4005 + 67 = 4072

55 - 56 = -1

4072 < -1

The answer is false.

4 0
3 years ago
Read 2 more answers
The equation r(t)= (3t+9)i+(sqrt(2)t)j+(t^2)k is the position of a particle in space at time t. Find the angle between the veloc
andreev551 [17]

Answer:

\theta= \frac{\pi}{2} +\pi \cdot i, for all i = \mathbb{Z} \cup\{0\}

Step-by-step explanation:

The velocity vector is found by deriving the position vector depending on the time:

\dot r(t)= v (t) = 3 \cdot i +\sqrt{2} \cdot j + 2\cdot t \cdot k

In turn, acceleration vector is found by deriving the velocity vector depending on time:

\ddot r(t) = \dot v(t) = a(t) = 2 \cdot k

Velocity and acceleration vectors at t = 0 are:

v(0) = 3\cdot i + \sqrt{2} \cdot j\\a(0) = 2 \cdot k\\

Norms of both vectors are, respectively:

||v(0)||\approx 3.317\\||a(0)|| \approx 2

The angle between both vectors is determined by using the following characteristic of a Dot Product:

\theta = \cos^{-1}(\frac{v(0) \bullet a(0)}{||v(0)||\cdot ||a(0)||})

Given that cosine has a periodicity of \pi. There is a family of solutions with the form:

\theta= \frac{\pi}{2} +\pi \cdot i, for all i = \mathbb{Z} \cup\{0\}

7 0
3 years ago
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