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tensa zangetsu [6.8K]
3 years ago
8

X²+9³×99=144342 Please help Ill mark as brainliest

Mathematics
1 answer:
maks197457 [2]3 years ago
6 0
  1. x=27
  1. First, since you are multiplying by 99 you have to do the opposite and divide by 99 on both sides to get x^2+9^3= 1458
  1. Next, you get rid of the exponent on the 9^3 by multiplying 9 * 9 * 9 to get 729 and subtract from both sides to get x^2 = 729
  1. Finally, you get rid of the exponent on the x by taking the square root of both sides to get x = 27
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Sveta_85 [38]

Step-by-step explanation:

when multiplied together, the gradients of the 2 graphs should equal -1 (of they are perpendicular).

x-7y=4

-7y= -x + 4

y= -1/7 x + 4/7

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3y=-21x+11

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3 years ago
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Answer:

\frac{dy}{dx}=-\frac{y}{3y^2+x}

Step-by-step explanation:

4-xy=y^3

dy/dx=?

\frac{d(4-xy)}{dx}=\frac{d(y^3)}{dx}\\ \frac{d(4)}{dx}-\frac{d(xy)}{dx}=3y^{3-1}\frac{dy}{dx}\\ 0-(\frac{dx}{dx}y+x\frac{dy}{dx})=3y^2\frac{dy}{dx}\\ -(1y+x\frac{dy}{dx})=3y^2\frac{dy}{dx}\\ -(y+x\frac{dy}{dx})=3y^2\frac{dy}{dx}\\ -y-x\frac{dy}{dx}=3y^2\frac{dy}{dx}

Solving for dy/dx: Addind x dy/dx both sides of the equation:

-y-x\frac{dy}{dx}+x\frac{dy}{dx}=3y^2\frac{dy}{dx}+x\frac{dy}{dx} \\ -y=3y^2\frac{dy}{dx}+x\frac{dy}{dx}

Common factor dy/dx on the right side of the equation:

-y=(3y^2+x)\frac{dy}{dx}

Dividing both sides of the equation by 3y^2+x:

\frac{-y}{3y^2+x}=\frac{(3y^2+x)}{3y^2+x}\frac{dy}{dx}\\ -\frac{y}{3y^2+x}=\frac{dy}{dx}\\ \frac{dy}{dx}=-\frac{y}{3y^2+x}

7 0
3 years ago
What is the answer to this equation? <br> 6(x-7)+10
SOVA2 [1]

Answer:

32

Step-by-step explanation:

7 0
3 years ago
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gladu [14]

Answer:

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formula: gradient of line one x gradient of line two= -1 (applies for 2 perpendicular lines only).

So, m1 x -1/3= -1

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4 0
3 years ago
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