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3 years ago

If t(n) = 3n-5 What is the 3rd term?

Mathematics

1 answer:

djverab [1.8K]3 years ago

3 0

T(3)=3x3-5
t(3)=9-5
t(3)=4

The third term is 4.

Hope this helps :)

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WRITE THE TERM,FILL IN THE BLANK

lianna [129]

The answer you’re looking for is: simplify.

When you rewrite an expression, we are simplifying it. We first use the distributive property through any groupings symbols, then evaluate terms we exponent that are given. Lastly, we combine any like terms, weather they are constants or variables.

Hope this helps! :)

5 0

3 years ago

Read 2 more answers

$32.00for a 14 2/9 km taxi ride. What is the cost per kilometer

KonstantinChe [14]

$\begin{array}{ccll} \$&km\\ \cline{1-2} 32&14\frac{2}{9}\\[1em] x&1 \end{array}\implies \cfrac{32}{x}=\cfrac{14\frac{2}{9}}{1}\implies \cfrac{32}{x}=14\frac{2}{9}\implies \cfrac{32}{x}=\cfrac{14\cdot 9+2}{9} \\\\\\ \cfrac{32}{x}=\cfrac{128}{9}\implies 288=128x\implies \cfrac{288}{128}=x\implies \stackrel{~\hfill \textit{2 bucks and 25 cents}}{\cfrac{9}{4}=x\implies 2\frac{1}{4}}=x$

4 0

2 years ago

2. Two angle measures are in the ratio 5:9. Write

iris [78.8K]

The two angles are x and 9x/5

Let the two angles we require be x and y.

<h3 /><h3>Ratio of both angles</h3>

We have that the ratio of both angles are x:y

Since both angles are in the ratio 5:9, we have that,

x:y = 5:9

⇒ x/y = 5/9

<h3 /><h3>Value of the other angle</h3>

So, we Make y subject of the formula

Multiplying both sides by y, we have

y × x/y = 5/9 × y

x = 5y/9

Multiplying both sides by 9, we have

9 × x = 5y/9 × 9

9x = 5y

Dividing both sides by 5, we have

9x/5 = 5y/5

y = 9x/5

So, the two angles are x and 9x/5

Learn more about angles here:

brainly.com/question/14362353

3 0

2 years ago

Kryptonite is a material found on the planet Krypton and has various effects, most importantly on Superman. The most common type

Rashid [163]

Answer:

The maximum amount of red kryptonite present is 33.27 g after 4.93 hours.

Step-by-step explanation:

dy/dt = y(1/t - k)

separating the variables, we have

dy/y = (1/t - k)dt

dy/y = dt/t - kdt

integrating both sides, we have

∫dy/y = ∫dt/t - ∫kdt

㏑y = ㏑t - kt + C

㏑y - ㏑t = -kt + C

㏑(y/t) = -kt + C

taking exponents of both sides, we have

$\frac{y}{t} = e^{-kt + C} \\\frac{y}{t} = e^{-kt}e^{C} \\\frac{y}{t} = Ae^{-kt} (A = e^{C})\\y = Ate^{-kt}$

when t = 1 hour, y = 15 grams. So,

$y = Ate^{-kt}\\15 = A(1)e^{-kX1}\\15 = Ae^{-k}$ (1)

when t = 3 hours, y = 30 grams. So,

$y = Ate^{-kt}\\30 = A(3)e^{-kX3}\\30 = 3Ae^{-3k}$ (2)

dividing (2) by (1), we have

$\frac{30}{15} = \frac{3Ae^{-3k}}{Ae^{-k}} \\2 = 3e^{-2k}\\\frac{2}{3} = e^{-2k}$

taking natural logarithm of both sides, we have

-2k = ㏑(2/3)

-2k = -0.4055

k = -0.4055/-2

k = 0.203

From (1)

$A = 15e^{k} \\A = 15e^{0.203} \\A = 15 X 1.225\\A = 18.36$

Substituting A and k into y, we have

$y = 18.36te^{-0.203t}$

The maximum value of y is obtained when dy/dt = 0

dy/dt = y(1/t - k) = 0

y(1/t - k) = 0

Since y ≠ 0, (1/t - k) = 0.

So, 1/t = k

t = 1/k

So, the maximum value of y is obtained when t = 1/k = 1/0.203 = 4.93 hours

$y = 18.36(1/0.203)e^{-0.203t}\\y = \frac{18.36}{0.203}e^{-0.203X1/0.203}\\y = 90.44e^{-1}\\y = 90.44 X 0.3679\\y = 33.27 g$

<u>So the maximum amount of red kryptonite present is 33.27 g after 4.93 hours.</u>

3 0

3 years ago

Write 4.51 as a mixed number and as an improper fraction.

anyanavicka [17]

it will be 451/100 as an improper fraction! :)

7 0

3 years ago