these inequalities can be solved just like equations
a. x - 7 > 25
+ 7 +7 x > 32the number line would have a filled in circle at 32 with an arrow pointing to the rightb. x - 8 < 5+8 +8x < 13 the number line would have an empty circle at 13 with an arrow pointing to the leftc.x + 11 > 23 - 11 - 11x > 12the number line would have an empty circle at 12 with an arrow pointing to the rightd. x + 12 < 6 - 12 - 12 x < -6the number line would have a filled in circle at -6 with an arrow pointing to the lefta. 21 < x + 18 -18 -18 3 < xx > 3b. 16 < x - 7 + 7 + 7 23 < x x > 23c. 12 > x - 7 + 7 + 7 19 > x x < 19d. 29 < x + 53 - 53 - 53 -24 < x x > -24e. 15 > x + 19 -19 -19 -4 > x x < -4f. 35 > x - 8 +8 +8 43 > x x < 43g. -6 < x - 18 +18 +18 12 < x x > 12h. -15 < x - 2 + 2 +2 -13 < x x > -13
Answer:
12 which is on C
Step-by-step explanation:
use pathogoras theorem
a^2+b^2=c^2
16^2+b^2=20^2
256+b^2=400
b^2=400-256
b^2=144
b= square root of 144
b= 12
2^2=4 so divid 36/4 is 9 and 4*2=8 now subtract 9-8=1 next 36/1 = 36 same on top is 8 now 36-8=28. 28 - 8 is 20 then 20-8= 12 answer is 12
Answer:
f(x) = x - 3
Step-by-step explanation:
y = mx + b
first let's find b, the y-intercept
based on the graph, the y-intercept is (0,-3), so b = -3
immediately, we can eliminate f(x) = 3 - x and f(x) = -3x
comment any questions pls
