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8090 [49]
3 years ago
10

8 by the power of -5

Mathematics
1 answer:
Paha777 [63]3 years ago
8 0

Answer:

In significant figure is

3.051757813 \times 1 {0}^{ - 05}

You can turn it into normal decimal number.

In decimal number:

0.0000305175713

Hope this will help :))

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WRITE THE SOLUTION TO THE FOLLOWING SYSTEMS<br> HURRY ILL GIVE BRAINLIEST!!!!!!!
Virty [35]

Answer:

1)     (2,4)

2)    (5,-2)

Step-by-step explanation:

those are the points at which the lines cross making them the solutions to the equations

4 0
3 years ago
The bill for your dinner is $91. You leave a $15.47 tip. What is the percent of tip?
mixas84 [53]

Answer: 17%

Step-by-step explanation:

15.47 over 91 = x over 100

cross multiply and reduce to find 17.

4 0
2 years ago
a container of candy is shaped like a cylinder and has a volume of 125.6 cubic centimeters. If the heights of the container is 1
Elenna [48]

The radius of the container is 2 centimeter

<h3><u>Solution:</u></h3>

Given that a container of candy is shaped like a cylinder

Given that volume = 125.6 cubic centimeters

Height of conatiner = 10 centimeter

To find: radius of the container

We can use volume of cylinder formula and obatin the radius value

<em><u>The volume of cylinder is given as:</u></em>

\text {volume of cylinder }=\pi r^{2} h

Where "r" is the radius of cylinder

"h" is the height of cylinder and \pi is constant has value 3.14

Substituting the values in formula, we get

\begin{array}{l}{125.6=3.14 \times r^{2} \times 10} \\\\ {r^{2}=\frac{125.6}{31.4}} \\\\ {r^{2}=4}\end{array}

Taking square root on both sides,

r = \sqrt{4}\\\\r = 2

Thus the radius of the container is 2 centimeter

4 0
3 years ago
What is the value of x ?<br> A. 55 <br> B. 50<br> C. 160<br> D. 20
lakkis [162]
The correct option would be C
6 0
2 years ago
You answer 32 questions correctly on a 45 question test. You need a score of at least 70% to pass. Do you pass? Explain
Taya2010 [7]

Answer:

Yes

Step-by-step explanation:

32 divided by 45 = .7111111111111111111

7 0
3 years ago
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