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3 years ago

What is the correct answer for thee equation 2 subtracted from 2 in mathematics?

Mathematics

2 answers:

rodikova [14]3 years ago

4 0

So 2 subtracted from 2 means
2 taken away from 2 or
2-2=0

Strike441 [17]3 years ago

3 0

<span>2 subtracted from 2 is 2 minus 2 and 2 minus(-) 2 is 0 so the answer is 0</span>

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Pencils come in packages of 10 . Erasers come in package of 12 . Phillip wants to purchase the smallest number of pencils and er

Maslowich

Answer: 60

Step-by-step explanation:

From the question, we are informed that pencils come in packages of 10 while erasers come in package of 12 .

We are further told that Phillip wants to purchase the smallest number of pencils and erasers so that he will have exactly 1 eraser per pencil, this simply means that we have to calculate the lowest common multiple for 10 and 12.

Multiples of 10 = 10, 20, 30, 40, 50, 60,

Multiples of 12 = 12, 24, 36, 48, 60, 72

Therefore, the packages of pencils and erasers that Phillip should buy will be 60

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3 years ago

What is the surface area of the figure? Use 3.14 for π....PLEASE HELP....NEED HELP ASAP

raketka [301]

Answer:

Step-by-step explanation:

Always use your imaginary scissor:

Cut the above and below circle and the cylinder role it down-ways like a carpet and you will end up with two circles and a big rectangular.

Surface circle: 7 * 7 * 3,14 = 153.86

Surface carpet: 20 * circle exterior (or the length of the circle)= 20 * 2* 3.14 * 7

Results:

153, 86 * 2 (because we cut 2 circles from the cylinder) + 132,6 = 439.6

Answer: A

3 0

3 years ago

Read 2 more answers

(PLEASE HELP I WILL GIVE BRAINLIEST IF CORRECT (40 POINTS)

Andrews [41]

Answer:

2800 - 4000

Step-by-step explanation:

40 × 70 = 2800

50 × 80 = 4000

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3 years ago

2 points) Sometimes a change of variable can be used to convert a differential equation y′=f(t,y) into a separable equation. One

Stells [14]

$y'=(t+y)^2-1$

Substitute $u=t+y$ , so that $u'=y'$ , and

$u'=u^2-1$

which is separable as

$\dfrac{u'}{u^2-1}=1$

Integrate both sides with respect to $t$ . For the integral on the left, first split into partial fractions:

$\dfrac{u'}2\left(\frac1{u-1}-\frac1{u+1}\right)=1$

$\displaystyle\int\frac{u'}2\left(\frac1{u-1}-\frac1{u+1}\right)\,\mathrm dt=\int\mathrm dt$

$\dfrac12(\ln|u-1|-\ln|u+1|)=t+C$

Solve for $u$ :

$\dfrac12\ln\left|\dfrac{u-1}{u+1}\right|=t+C$

$\ln\left|1-\dfrac2{u+1}\right|=2t+C$

$1-\dfrac2{u+1}=e^{2t+C}=Ce^{2t}$

$\dfrac2{u+1}=1-Ce^{2t}$

$\dfrac{u+1}2=\dfrac1{1-Ce^{2t}}$

$u=\dfrac2{1-Ce^{2t}}-1$

Replace $u$ and solve for $y$ :

$t+y=\dfrac2{1-Ce^{2t}}-1$

$y=\dfrac2{1-Ce^{2t}}-1-t$

Now use the given initial condition to solve for $C$ :

$y(3)=4\implies4=\dfrac2{1-Ce^6}-1-3\implies C=\dfrac3{4e^6}$

so that the particular solution is

$y=\dfrac2{1-\frac34e^{2t-6}}-1-t=\boxed{\dfrac8{4-3e^{2t-6}}-1-t}$

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3 years ago

Nacy has 8 pieces of string that are exactly the same length

Taya2010 [7]

Answer:

Well there you go she has 8 pieces of string wit the same length

Step-by-step explanation: If they the same length then they the same length all you have to do is read

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4 years ago