If a triangle has sides of lengths 3, 4, and 5 units, then it is
1 answer:
Answer:
If a triangle has side lengths 3, 4, and 5 units, then its area is 6
Step-by-step explanation:
<em><u>Deductive reasoning </u></em>represents an important form of logical reasoning in which a conclusion is based on the concordance of multiple premises that are generally assumed to be true
we have
If a triangle has side lengths 3, 4, and 5 units, then its area is 6
we know that
1) If triangle has side lengths 3, 4 and 5, then is a right triangle because satisfy the Pythagoras Theorem
2) All right triangles have an area equal to one half the product of the two smaller side lengths
substitute the values
therefore
The statement is valid based on deductive reasoning
You might be interested in
The question is asking which formula will give the results
1, 9, 36, 100, 225, ...
for k values of
1, 2, 3, 4, 5, ...
You can try them out to see.
A) for k=2, gives 2*3/2 = 3 . . . not 9
B) for k=1, gives 2^3/3 = 8/3 . . . not 1
C) for k=2, gives (2^2*3^2)/4 = 9 . . . . looks promising
D) for k=1, gives 1*2^3/5 = 8/5 . . . not 1
Selection C is the only viable choice. (And the correct one.)
1, 9, 36, 100, 225, ...
for k values of
1, 2, 3, 4, 5, ...
You can try them out to see.
A) for k=2, gives 2*3/2 = 3 . . . not 9
B) for k=1, gives 2^3/3 = 8/3 . . . not 1
C) for k=2, gives (2^2*3^2)/4 = 9 . . . . looks promising
D) for k=1, gives 1*2^3/5 = 8/5 . . . not 1
Selection C is the only viable choice. (And the correct one.)