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3 years ago

What is 24% of 4,6 million

Mathematics

2 answers:

Masteriza [31]3 years ago

6 0

3,680,000 would be the answer

MArishka [77]3 years ago

5 0

That my lad is 1104000

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On a grocery store shelf, there are 16 loaves of white bread and 24 loaves of wheat bread. A shopper randomly selects a loaf of

Oksanka [162]

Answer:

60%

Step-by-step explanation:

16 loaves of white bread and 24 loaves of wheat bread. = 40 loaves of bread

P( wheat) = number of wheat/ total

= 24/40

=.6

=60%

4 0

2 years ago

Isabella's teacher said she must read more than 70 pages of her book by the end of the week. Isabella is able to read 12 pages o

AlexFokin [52]

Answer:

She must read more than 5 more hours.

Step-by-step explanation:

4 0

3 years ago

Help please! asap!

aliya0001 [1]

Answer: 50% or 1/2

Step-by-step explanation:

number of possible combos:

1+1, 1+2, 1+3, 1+4, 1+5, 1+6

2+1, 2+2, 2+3, 2+4, 2+5, 2+6

3+1, 3+2, 3+3, 3+4, 3+5, 3+6

4+1, 4+2, 4+3, 4+4, 4+5, 4+6

5+1, 5+2, 5+3, 5+4, 5+5, 5+6

6+1, 6+2, 6+3, 6+4, 6+5, 6+6

number of even sums within combos:

1+1, 1+3, 1+5

2+2, 2+4, 2+6

3+1, 3+3, 3+5

4+2, 4+4, 4+6

5+1, 5+3, 5+5

6+2, 6+4, 6+6

TOTAL combos:

TOTAL even sums:

so that means 18/36 or 1/2 of the possible combinations has a sum of an even number.

sorry it’s not a table but I literally worked it out while answering so that’s all my work

8 0

2 years ago

PLEASE HELP QUICKLY 25 POINTS

Natalija [7]

Answer:

○ $\displaystyle \pi$

Step-by-step explanation:

$\displaystyle \boxed{y = 3sin\:(2x + \frac{\pi}{2})} \\ y = Asin(Bx - C) + D \\ \\ Vertical\:Shift \hookrightarrow D \\ Horisontal\:[Phase]\:Shift \hookrightarrow \frac{C}{B} \\ Wavelength\:[Period] \hookrightarrow \frac{2}{B}\pi \\ Amplitude \hookrightarrow |A| \\ \\ Vertical\:Shift \hookrightarrow 0 \\ Horisontal\:[Phase]\:Shift \hookrightarrow \frac{C}{B} \hookrightarrow \boxed{-\frac{\pi}{4}} \hookrightarrow \frac{-\frac{\pi}{2}}{2} \\ Wavelength\:[Period] \hookrightarrow \frac{2}{B}\pi \hookrightarrow \boxed{\pi} \hookrightarrow \frac{2}{2}\pi \\ Amplitude \hookrightarrow 3$

OR

$\displaystyle \boxed{y = 3cos\:2x} \\ y = Acos(Bx - C) + D \\ \\ Vertical\:Shift \hookrightarrow D \\ Horisontal\:[Phase]\:Shift \hookrightarrow \frac{C}{B} \\ Wavelength\:[Period] \hookrightarrow \frac{2}{B}\pi \\ Amplitude \hookrightarrow |A| \\ \\ Vertical\:Shift \hookrightarrow 0 \\ Horisontal\:[Phase]\:Shift \hookrightarrow 0 \\ Wavelength\:[Period] \hookrightarrow \frac{2}{B}\pi \hookrightarrow \boxed{\pi} \hookrightarrow \frac{2}{2}\pi \\ Amplitude \hookrightarrow 3$

You will need the above information to help you interpret the graph. First off, keep in mind that although this looks EXACTLY like the cosine graph, if you plan on writing your equation as a function of sine, then there WILL be a horisontal shift, meaning that a C-term will be involved. As you can see, the photograph on the right displays the trigonometric graph of $\displaystyle y = 3sin\:2x,$ in which you need to replase "cosine" with "sine", then figure out the appropriate C-term that will make the graph horisontally shift and map onto the sine graph [photograph on the left], accourding to the horisontal shift formula above. Also keep in mind that the −C gives you the OPPOCITE TERMS OF WHAT THEY REALLY ARE, so you must be careful with your calculations. So, between the two photographs, we can tell that the sine graph [photograph on the right] is shifted $\displaystyle \frac{\pi}{4}\:unit$ to the right, which means that in order to match the cosine graph [photograph on the left], we need to shift the graph BACKWARD $\displaystyle \frac{\pi}{4}\:unit,$ which means the C-term will be negative, and by perfourming your calculations, you will arrive at $\displaystyle \boxed{-\frac{\pi}{4}} = \frac{-\frac{\pi}{2}}{2}.$ So, the sine graph of the cosine graph, accourding to the horisontal shift, is $\displaystyle y = 3sin\:(2x + \frac{\pi}{2}).$ Now, with all that being said, in this case, sinse you ONLY have a graph to wourk with, you MUST figure the period out by using wavelengths. So, looking at where the graph WILL hit $\displaystyle [-1\frac{3}{4}\pi, 0],$ from there to $\displaystyle [-\frac{3}{4}\pi, 0],$ they are obviously $\displaystyle \pi\:units$ apart, telling you that the period of the graph is $\displaystyle \pi.$ Now, the amplitude is obvious to figure out because it is the A-term, but of cource, if you want to be certain it is the amplitude, look at the graph to see how low and high each crest extends beyond the midline. The midline is the centre of your graph, also known as the vertical shift, which in this case the centre is at $\displaystyle y = 0,$ in which each crest is extended three units beyond the midline, hence, your amplitude. So, no matter how far the graph shifts vertically, the midline will ALWAYS follow.