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IceJOKER [234]
3 years ago
12

Find the area of an equilateral triangle (regular 3-gon) with the given measurement.

Mathematics
1 answer:
Paul [167]3 years ago
8 0

Using Heron's formula where s = 9 ...... and a = b = c = the side lengths .....we have......

A = √[s(s -a)^3] = √[4*3^3] = √[4*27] = √[4*9*3] = √[36*3) = 9√3 sq. in.

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Step-by-step explanation:

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Which of the following lines is parallel to the
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7. Lin is reading a 146-page book. She read the first 20 pages in 35 minutes. 1 point How many minutes does it take her to finis
natita [175]

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255.5 minutes or 255 minutes and 30 seconds

Step-by-step explanation:

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7 0
3 years ago
An on-the-job injury occurs once every 10 days on
ExtremeBDS [4]

The probability that the next on-the-job injury will occur within 10, 5, and 1 day are 0.632, 0.393, and 0.095

<h3>What is probability?</h3>

It is defined as the ratio of the number of favourable outcomes to the total number of outcomes, in other words, the probability is the number that shows the happening of the event.

We know the exponential distribution is given by;

\rm P(X < t)=1-e^{-\dfrac{1}{\mu}t}

The probability that the next on-the-job injury will occur within 10 days:

\rm P(X < 10)=1-e^{-\dfrac{1}{10}10}

P(X< 10) = 0.632

The probability that the next on-the-job injury will occur within 20 days:

\rm P(X < 5)=1-e^{-\dfrac{1}{10}5}

P(X< 5) = 0.393

The probability that the next on-the-job injury will occur within 1 days:

\rm P(X < 1)=1-e^{-\dfrac{1}{10}1}

P(X< 1) = 0.095

Thus, the probability that the next on-the-job injury will occur within 10, 5, and 1 day are 0.632, 0.393, and 0.095

Learn more about the probability here:

brainly.com/question/11234923

#SPJ1

5 0
2 years ago
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