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Gemiola [76]
3 years ago
7

Between what two integers on a number line would \sqrt[3]{35}35 3 be plotted?

Mathematics
2 answers:
zhannawk [14.2K]3 years ago
7 0

Answer: Answer is 5between 6

Step-by-step explanation:Look up khan Academy video on google if you need a clear answer expressed

ludmilkaskok [199]3 years ago
6 0

Answer:

5 and 6

Step-by-step explanation:

Because 35 is between 25 and 36.

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Say he had $500 on his card. He took 0 rides ( no rides ) so he doesn't lose any money. Leaving him with his starting amount, $500.

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An article regarding interracial dating and marriage recently appeared in the Washington Post. Of the 1,709 randomly selected ad
VMariaS [17]

Answer:

The 95% confidence interval for the percent of all black adults who would welcome a white person into their families is (0.8222, 0.8978).

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of \pi, and a confidence level of 1-\alpha, we have the following confidence interval of proportions.

\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}

In which

z is the zscore that has a pvalue of 1 - \frac{\alpha}{2}.

For this problem, we have that:

323 blacks, 86% of blacks said that they would welcome a white person into their families. This means that n = 323, p = 0.86

95% confidence level

So \alpha = 0.05, z is the value of Z that has a pvalue of 1 - \frac{0.05}{2} = 0.975, so Z = 1.96.

The lower limit of this interval is:

\pi - z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.86 - 1.96\sqrt{\frac{0.86*0.14}{323}} = 0.8222

The upper limit of this interval is:

\pi + z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.86 + 1.96\sqrt{\frac{0.86*0.14}{323}} = 0.8978

The 95% confidence interval for the percent of all black adults who would welcome a white person into their families is (0.8222, 0.8978).

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