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Gemiola [76]
3 years ago
7

Between what two integers on a number line would \sqrt[3]{35}35 3 be plotted?

Mathematics
2 answers:
zhannawk [14.2K]3 years ago
7 0

Answer: Answer is 5between 6

Step-by-step explanation:Look up khan Academy video on google if you need a clear answer expressed

ludmilkaskok [199]3 years ago
6 0

Answer:

5 and 6

Step-by-step explanation:

Because 35 is between 25 and 36.

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Write two different pairs of decimals whose sums are 8.69. One pair should involve regrouping
chubhunter [2.5K]
One pair is 4.345+4.345 (which is the pair that does not involve grouping)
7 0
3 years ago
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Simplify the expression: the square root of -13 times the square root of -26 calculator
Rasek [7]
Sqrt -13  = sqrt13 i
sqrt  -26  =  sqrt2 * sqrt13i 

sqrt-13 * sqrt -26  = sqrt2 * 13*  i^2  = -13 sqrt2 (because i^2 = -1)

answer is -13 sqrt2
6 0
3 years ago
A rectangular storage container with a lid is to have a volume of 2 m3. The length of its base is twice the width. Material for
Scilla [17]

Answer:

Dimensions are 2 m by 1 meter by 1 meter,

Minimum cost is $ 18.

Step-by-step explanation:

Let w be the width ( in meters ) of the container,

Since, the length is twice of the width,

So, length of the container = 2w,

Now, if h be the height of the container,

Volume = length × width × height

2 = 2w × w × h

1 = w² × h

\implies h=\frac{1}{w^2}

Since, the area of the base = l × w = 2w × w = 2w²,

Area of the lid = l × w = 2w²,

While the area of the sides = 2hw + 2hl

= 2h( w + l)

= 2\times \frac{1}{w^2}(w+2w)

=\frac{6w}{w^2}

=\frac{6}{w}  

Since, Material for the base costs $1 per m². Material for the sides and lid costs $2 per m²,

So, the total cost,

C(w) = 1\times 2w^2+2\times 2w^2 + 2\times \frac{6}{w}

=2w^2+4w^2+\frac{12}{w}

=6w^2+\frac{12}{w}

Differentiating with respect to w,

C'(w) = 12w -\frac{12}{w^2}

Again differentiating with respect to w,

C''(w) = 12 + \frac{24}{w^3}

For maxima or minima,

C'(w) = 0

\implies 12w -\frac{12}{w^2}=0

\implies 12w^3 - 12=0

w^3-1=0\implies w = 1

For w = 1, C''(w) = positive,

Hence, for width 1 m the cost is minimum,

Therefore, the minimum cost is C(1) = 6(1)²+12 = $ 18,

And, the dimension for which the cost is minimum is,

2 m by 1 meter by 1 meter.

7 0
3 years ago
Please help sorry if it’s a little blurry! I’ll mark brainliest if you tell me why you got that answer.
sergij07 [2.7K]

Answer:

Hi! Saw your comment saying you got it, congrats! I hope you are having an amazing day/night and I wish you luck with the rest of your studies! I hope you don't mind that I use this for some points! <3

3 0
3 years ago
I am confused on how to get the answer
Ksju [112]

Answer:

try using this

Step-by-step explanation:

multiply  π  which = 3.14 by the diamiter so it would be 3.14 x 6.5 = 20.41

4 0
3 years ago
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