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gulaghasi [49]
2 years ago
8

Q =3x2+5x-2 R = 2 – x2 S = 2x + 5 Find Q – [R + S] Show all of the steps.

Mathematics
1 answer:
matrenka [14]2 years ago
5 0

Q=3x^2+5x-2\\R=2-x^2\\S=2x+5\\\\Q-[R+S]=(3x^2+5x-2)-[(2-x^2)+(2x+5)]\\\\=(3x^2+5x-2)-(2-x^2+2x+5)\\\\=(3x^2+5x-2)-[-x^2+2x+(2+5)]\\\\=(3x^2+5x-2)-(-x^2+2x+7)\\\\=3x^2+5x-2-(-x^2)-2x-7\\\\=3x^2+5x-2+x^2-2x-7\\\\=(3x^2+x^2)+(5x-2x)+(-2-7)\\\\=\boxed{4x^2+3x-9}

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ikadub [295]

Answer:

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Step-by-step explanation:

6 0
2 years ago
The slope of the line below is -3. Is the coordinates of the labeled point to find a point - slope equation of the line
puteri [66]
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where y and x stay the same

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and (a, b) (any coordinate on the graph)

based on the point (5, -7)

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however, the - cancels out the negative 7 making I positive

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3 0
3 years ago
HELP I NEED HELP ASAP
cricket20 [7]

Answer:

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Step-by-step explanation:

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6 0
2 years ago
Slope =-1, y-intercept = 3
ss7ja [257]

If you are looking for the equation, then it would be y = -x+3

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m = -1 = slope

b = 3 = y intercept

If you want to graph this, then plot the points (0,3) and (1,2). Then draw a straight line through them both. Extend the line in both directions as much as possible.

7 0
2 years ago
Read 2 more answers
write an equation in slope intercept form for the line that is perpendicular to y=-1/4x+2 and passes through the points (-4,3)
PilotLPTM [1.2K]
For lines to be perpendicular their slopes must be negative reciprocals of one another, mathematically:

m1*m2=-1, and in this case:

-m/4=-1

-m=-4

m=4, so the slope of the perpendicular line is 4 so we have thus far:

y=4x+b, using point (-4,3) we can solve for the y-intercept, "b"

3=4(-4)+b

3=-16+b

19=b, so our line is:

y=4x+19
8 0
3 years ago
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