Q =3x2+5x-2 R = 2 – x2 S = 2x + 5 Find Q – [R + S] Show all of the steps.

1 answer:

5 0

$Q=3x^2+5x-2\\R=2-x^2\\S=2x+5\\\\Q-[R+S]=(3x^2+5x-2)-[(2-x^2)+(2x+5)]\\\\=(3x^2+5x-2)-(2-x^2+2x+5)\\\\=(3x^2+5x-2)-[-x^2+2x+(2+5)]\\\\=(3x^2+5x-2)-(-x^2+2x+7)\\\\=3x^2+5x-2-(-x^2)-2x-7\\\\=3x^2+5x-2+x^2-2x-7\\\\=(3x^2+x^2)+(5x-2x)+(-2-7)\\\\=\boxed{4x^2+3x-9}$

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Write the equation of the line that passes through the points (7,9) and

nevsk [136]

Step-by-step explanation:

9 = a7 + b

-2 = a9 + b

b = 9-7a and b = - 2-9a

9 - 7a = - 2-9a

2a = - 11

a = - 5.5

b = 9 - 5.5*7 = - 29.5

y = -5.5x - 29.5

5 0

3 years ago

Can someone explain to me how to do this?

elena55 [62]

In the slope intercept form equation of a line (y=ax+b) a represents the slope, and b represents the intercept, which is -5. Thus, we know y=ax-5. The slope can be found by creating a fraction with the change in y value on top, and the change of x value on the bottom. If we have two points (4, 1) and (0, -5) we can put this into a fraction - $\frac{-5-1}{0-4}$ , which simplifies down to -6/-4, or 3/2. Thus the answer is f(x)= $\frac{3}{2}$ x-5<span />