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gulaghasi [49]
3 years ago
8

Q =3x2+5x-2 R = 2 – x2 S = 2x + 5 Find Q – [R + S] Show all of the steps.

Mathematics
1 answer:
matrenka [14]3 years ago
5 0

Q=3x^2+5x-2\\R=2-x^2\\S=2x+5\\\\Q-[R+S]=(3x^2+5x-2)-[(2-x^2)+(2x+5)]\\\\=(3x^2+5x-2)-(2-x^2+2x+5)\\\\=(3x^2+5x-2)-[-x^2+2x+(2+5)]\\\\=(3x^2+5x-2)-(-x^2+2x+7)\\\\=3x^2+5x-2-(-x^2)-2x-7\\\\=3x^2+5x-2+x^2-2x-7\\\\=(3x^2+x^2)+(5x-2x)+(-2-7)\\\\=\boxed{4x^2+3x-9}

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Answer:

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Answer:

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Step-by-step explanation:

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