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IrinaVladis [17]
4 years ago
9

X-intercept=2; containing the point (-5,4), using either the general form or the slope-intercept form of the equation of a line.

Mathematics
1 answer:
Rus_ich [418]4 years ago
8 0
The line contains point (2, 0) and (-5, 4).
y - 0 = (4 - 0)/(-5 - 2) (x - 2)
y = -4/7 (x - 2)
7y = -4(x - 2)
7y = -4x + 8
4x + 7y = 8
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All employees at three stores of a large retail chain were asked to fill out a survey.a. Is it random b. Systematic c. Stratifie
aleksandrvk [35]

Answer:

d. Cluster

Step-by-step explanation:

Random: Random is asking a group of people from a population. For example, to estimate the proportion of Buffalo residents who are Bills fans, you ask 100 Buffalo residents and estimate to the entire population.

Systematic: Similar to random. For example, you want to estimate something about a population, and your sample is every 5th people you see on the street.

Cluster:Divides the population into groups, with geographic characteristics.. Each element is the groups is used. Suppose you want to study the voting choices of Buffalo Bills players. You can divide into offense, defense and special teams, and ask each player of these 3 groups.

Stratified: Done on a group of clusters, that is, from each cluster(group), a number of people are selected.

In this problem, we have that:

All employees at three stores of a large retail chain were asked to fill out a survey.

Divided by clusters(stores).

So the orrect answer is:

d. Cluster

5 0
4 years ago
Which best describes your ability to write and simplify expressions?
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6 0
4 years ago
Read 2 more answers
use the points (1998,13.60) and (2003,19.00) to write the slope intercept form of an equation for the line of fit shown in the s
Reika [66]
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so we have y=1.08x +b
next, use the point (2003, 19.00) to find b:
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so the equation is y=1.08x-2144.24
4 0
3 years ago
Let w(s,t)=f(u(s,t),v(s,t)) where u(1,0)=−6,∂u∂s(1,0)=5,∂u∂1(1,0)=7 v(1,0)=−8,∂v∂s(1,0)=−8,∂v∂t(1,0)=6 ∂f∂u(−6,−8)=−1,∂f∂v(−6,−8
Blababa [14]
w(s,t)=f(u(s,t),v(s,t))

From the given set of conditions, it's likely that you are asked to find the values of \dfrac{\partial w}{\partial s} and \dfrac{\partial w}{\partial t} at the point (s,t)=(1,0).

By the chain rule, the partial derivative with respect to s is

\dfrac{\partial w}{\partial s}=\dfrac{\partial f}{\partial u}\dfrac{\partial u}{\partial s}+\dfrac{\partial f}{\partial v}\dfrac{\partial v}{\partial s}

and so at the point (1,0), we have

\dfrac{\partial w}{\partial s}\bigg|_{(s,t)=(1,0)}=\dfrac{\partial f}{\partial 
u}\bigg|_{(u,v)=(-6,-8)}\dfrac{\partial u}{\partial s}\bigg|_{(s,t)=(1,0)}+\dfrac{\partial f}{\partial 
v}\bigg|_{(u,v)=(-6,-8)}\dfrac{\partial v}{\partial s}\bigg|_{(s,t)=(1,0)}
\dfrac{\partial w}{\partial s}\bigg|_{(s,t)=(1,0)}=(-1)(5)+(2)(-8)=-21

Similarly, the partial derivative with respect to t would be found via

\dfrac{\partial w}{\partial t}\bigg|_{(s,t)=(1,0)}=\dfrac{\partial f}{\partial 
u}\bigg|_{(u,v)=(-6,-8)}\dfrac{\partial u}{\partial t}\bigg|_{(s,t)=(1,0)}+\dfrac{\partial f}{\partial 
v}\bigg|_{(u,v)=(-6,-8)}\dfrac{\partial v}{\partial t}\bigg|_{(s,t)=(1,0)}
\dfrac{\partial w}{\partial t}\bigg|_{(s,t)=(1,0)}=(-1)(7)+(2)(6)=5
6 0
4 years ago
[5 Points] Please help. The picture below/above.
In-s [12.5K]
10x - 4 = 2x
8x = 4
  x = 1/2

answer is D. one real solution x = 1/2
8 0
4 years ago
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