What are some ways you could break apart 7 x 9 using the distributive property
1 answer:
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The table is attached as a figure
The given equation is ⇒⇒⇒⇒ y = 2x
To solve this equation, we need to pick numbers from the table then this number will be substituted into the equation to find y
we need 3 solutions . so, we need to pick 3 numbers of x
From the table, let us choose x = 0
y = 2x
y = 2 * (0)
y = 0
From the table, let choose second value of x such as x = 1
y = 2 * (1)
y = 2
From the table, let choose third value of x such as x = -1
y = 2 * (-1)
y = -2
So, the picked three solutions are
y = 0 at x = 0
y = -2 at x = -1
y = 2 at x = 1
The given equation is ⇒⇒⇒⇒ y = 2x
To solve this equation, we need to pick numbers from the table then this number will be substituted into the equation to find y
we need 3 solutions . so, we need to pick 3 numbers of x
From the table, let us choose x = 0
y = 2x
y = 2 * (0)
y = 0
From the table, let choose second value of x such as x = 1
y = 2 * (1)
y = 2
From the table, let choose third value of x such as x = -1
y = 2 * (-1)
y = -2
So, the picked three solutions are
y = 0 at x = 0
y = -2 at x = -1
y = 2 at x = 1
Answer:
Step-by-step explanation:
I'm goig to assume that the formula we need here is the following:
where A(t) is the amount in the account after the compounding is done, n is the number of times per year the compounding occurs, r is the rate in decimal form, and t is the time in years. Filling in accordingly,
and simplifying a bit,
and simplifying a bit more,
A(t) = 90000(1.343916379) so
the amount in the account after 5 years is
A(t) = 120,952.47