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4 years ago

Use the X intercept method to find all real solutions of the equation x^3-10x^2+17x+28=0

Mathematics

2 answers:

faust18 [17]4 years ago

7 0

Answer:

A. -1, 4, 7

Step-by-step explanation:

irakobra [83]4 years ago

6 0

Answer:

They are -1, 4 and 7.

Step-by-step explanation:

x^3 - 10x^2 + 17x + 28 = 0

Observation of this equation shows that there is an x -intercept at x = -1 because

-1^3 - 10^(-1)^2 - 17(1) + 28 = -28 + 28

= 0.

So x + 1 must be a factor so we can do the division:

x + 1 ) x^3 - 10x^2 + 17x + 28 ( x^2 - 11x + 28

x^3 + x^2

-11x^2 + 17x

-11x^2 - 11x

28x^2 + 28

x^2 - 11x + 28 = ( x - 4)(x - 7)

x = 4, 7.

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Nuetrik [128]

Answer:

2) m∠CBD = 25°

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4) m arc XY = 10°

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Step-by-step explanation:

2) ∵ the measure of arc BC = 130°

∵ Arc BCD is the semi-circle its measure 180°

∴ The measure of arc cd = 180 - 130 = 50°

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3 years ago

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mel-nik [20]

Answer:

Option (a) is correct.

Step-by-step explanation:

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Thus,

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