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disa [49]
3 years ago
12

Can someone plz help me solved this problem I need help ASAP plz help me! Will mark you as brainiest!

Mathematics
1 answer:
Over [174]3 years ago
8 0

Step-by-step explanation:

initial speed = 272 ft/s

h = -16t² + 272t

a. 1120 = -16t² + 272t we change a bit into

16t² - 272t + 1120 = 0 then divide all with factor 16

t² - 17t + 70 = 0

(t - 10)(t - 7) = 0

t = 10 and t = 7

7 s when it goes up and 10 sec when the rocket goes down.

b. 1152 = -16t² + 272t we change a bit into

16t² - 272t + 1152 = 0 then divide all with factor 16

t² - 17t + 72 = 0

(t - 9)(t - 8) = 0

t = 9 and t = 8 sec

c. since the answer of a and b is:

7 sec and 8 sec the rocket goes up but at 9 sec and 10 sec the rocket goes down then we can take conclusion that the maximum height is reached at 8.5 s

so how long the rocket in the air?

goes up : 8.5 sec

goes down : 8.5 sec

total = 17 sec

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Luis wants to buy a pair of jeans that costs $24. If the tax rate is
muminat

Answer:

25 68/100

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7 0
3 years ago
A local car dealer claims that 25% of all cars in San Francisco are blue. You take a random sample of 600 cars in San Francisco
sammy [17]

Answer:

No, we can't reject the dealer's claim with a significance level of 0.05.

Step-by-step explanation:

We are given that a local car dealer claims that 25% of all cars in San Francisco are blue.

You take a random sample of 600 cars in San Francisco and find that 141 are blue.

<u><em>Let p = proportion of all cars in San Francisco who are blue</em></u>

SO, Null Hypothesis, H_0 : p = 25%   {means that 25% of all cars in San Francisco are blue}

Alternate Hypothesis, H_A : p \neq 25%   {means that % of all cars in San Francisco who are blue is different from 25%}

The test statistics that will be used here is <u>One-sample z proportion</u> <u>statistics</u>;

                                  T.S.  = \frac{\hat p-p}{{\sqrt{\frac{\hat p(1-\hat p)}{n} } } } }  ~ N(0,1)

where, \hat p = sample proportion of 600 cars in San Francisco who are blue =   \frac{141}{600} = 0.235

            n = sample of cars = 600

So, <u><em>test statistics</em></u>  =  \frac{0.235-0.25}{{\sqrt{\frac{0.235(1-0.235)}{600} } } } }

                               =  -0.866

<em>Now at 0.05 significance level, the z table gives critical values of -1.96 and 1.96 for two-tailed test. Since our test statistics lies within the range of critical values of z so we have insufficient evidence to reject our null hypothesis as it will not fall in the rejection region due to which we fail to reject our null hypothesis.</em>

Therefore, we conclude that 25% of all cars in San Francisco are blue which means the dealer's claim was correct.

4 0
3 years ago
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