X - 5 = 27
Isolate the x, add 5 to both sides (because of equal sign)
x - 5 = 27
x - 5 (+5) = 27 (+5)
x = 27 + 5
x = 32
x = 32 is your answer
hope this helps
All of the above are true
Answer:
Step-by-step explanation:
If x - 1 is a factor of the cubic, then 1 should result in 0 when you put it in the cubic for x. Does it?
f(1) = 2(1)^3 - 15(1)^2 + 22(1) + 15
f(1) = 2 - 15 + 22 + 15
f(1)= 24.
No the result is not zero. So x - 1 is not a factor.
However there must be something that makes this cubic go to zero. The easiest way to find it is to graph it.
The numbers that do make this zero are -0.5, 3, 5
Which mean that the factors are (2x+1)(x-3)(x - 5)
Answer:
1:05 p.m
Step-by-step explanation:
they took 35 minutes...... and they arrived at 1:40 p.m so 40-35= 5 = 1:05 p.m :)
Answer:
9
Step-by-step explanation:
Because line PQ and line PR are both tangent to circle S, it would result in them being equal. So first to find PQ, you would have to find the value of variable x. To do this you would set both equations equal to each other and solve
6x - 9 = 2x + 3
-2x -2x
4x - 9 = 3
+9 +9
4x = 12
x = 3
Now you have to substitute 3 back into the equation for PQ:
6(3) - 9
18 - 9
= 9
Resulting in PQ = 9, to check your answer, take the value of x (3) and substitute it into PR and you should also get 9
2(3) + 3
6 + 3
= 9
