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3 years ago

F(x) = 9x – 10 f(4) =

Mathematics

2 answers:

lana66690 [7]3 years ago

4 0

Answer:

6551

Step-by-step explanation:

x=4

9 (4) - 10

9x9x9x9= 6561

6561-10= 6551

kaheart [24]3 years ago

4 0

Answer:

i thinkkkkk 100 :((((())))

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How do i reduce a shape by using the scale factor 2:1

bearhunter [10]

Answer: i think you're talking about dilations and there are specific formulas depending on the situation.

for example: the dilation of (x,y) is (-1/2x, -1/2y).

you'd probably need to subtract 2 from whatever measurements of the shape you're working with. i'm not completely sure though

3 0

2 years ago

If Ms. P wants to withdraw $900 from an account earning 4% average annual interest rate at the start of each year for 7 years, h

Ksju [112]

Answer:

Amount he must have in his account today is $5,617.92

Step-by-step explanation:

Data provided in the question:

Regular withdraw amount = $900

Average annual interest rate, i = 4% = 0.04

Time, n = 7 years

Now,

Present Value = $C \times\left[ \frac{1-(1+i)^{-n}}{i} \right] \times(1 + i)$

here,

C = Regular withdraw amount

Thus,

Present Value = $C \times\left[ \frac{1-(1+i)^{-n}}{i} \right] \times(1 + i)$

Present Value = $900 \times\left[ \frac{1-(1+0.04)^{-7}}{ 0.04 } \right] \times(1 + 0.04)$

Present Value = $936 \times\left[ \frac{1 - 1.04^{-7}}{ 0.04} \right]$

Present Value = $936 \times\left[ \frac{1 - 0.759918}{ 0.04} \right]$

Present Value = 936 × 6.00205

Present Value = $5,617.92

Hence,

Amount he must have in his account today is $5,617.92

7 0

3 years ago

6.3.6. Among the early attempts to revisit the death postponement theory introduced in Case Study 6.3.2 was an examination of th

kakasveta [241]

Answer:

So the Null hypothesis is rejected in this case

Step-by-step explanation:

The number of celebrities is n = 348

So to solve this we would assume that p is the percentage of people that died on the month preceding their birth month

Generally if there is no death postponement then p will be mathematically evaluated as

$p = \frac{1}{12}$

This implies the probability of date in one month out of the 12 months

Now from the question we can deduce that the hypothesis we are going to be testing is

$Null Hypothesis \ \ H_0 : p = 0.083$

This is a hypothesis is stating that a celebrity dies in the month preceding their birth

$Alternative \ Hypothesis H_1 : p < 0.083$

This is a hypothesis is stating that a celebrity does not die in the month preceding their birth

is c is the represent probability for each celebrity which either c = 0 or c = 1

Where c = 0 is that the probability that the celebrity does not die on the month preceding his/ her birth month

and c = 1 is that the probability that the celebrity dies on the month preceding his/ her birth month

Then it implies that

for

n= 1 + 2 + 3 + .... + 348 celebrities

Then the sum of c for each celebrity would be $c_s = 16$

i.e The number of celebrities that died in the month preceding their birth month

We are told that the significance level is $\alpha = 0.05$ , the the z value of $\alpha$ is

$z_{\alpha } = 1.65$

This is obtained from the z-table

Since this test is carried out on the left side of the area under the normal curve then the critical value will be

$z_{\alpha } = - 1.65$

So what this implies is that $H_o$ will be rejected if

$z \le -1.65$

Here z is the test statistics

Now z is mathematically evaluated as follows

$z = \frac{c - np}{\sqrt{np_o(1- p_o)} }$

$z = \frac{16 - (348 *0.083)}{\sqrt{348*0.083 (1- 0.083)} }$

$z =-2.50$

From our calculation we see that the value of z is less than $-1.65$ so the Null hypothesis will be rejected

Hence this tell us that the evidence provided is not enough to conclude that 16 celebrities died a month to their birth month

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3 years ago

A light bulb consumes 9450 W in five days in six hours how many watt hours does a consume per day?

KengaRu [80]

Well first 9450/5=1890 then 1890/6= 315 watt hours per day

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3 years ago

How do you know the correct order in which to evaluate algebraic expressions?

GenaCL600 [577]

You should use PEMDAS. I

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2 years ago