(0,5.25)(10,13.75)
slope(m) = (y2 - y1) / (x2 - x1)
slope(m) = (13.75 - 5.25) / (10 - 0) = 8.5/10 = 0.85
y = mx + b
(0,5.25)...x = 0 and y = 5.25
slope(m) = 0.85
now we sub, we r looking for b, the y int
5.25 = 0.85(0) + b
5.25 = b
so ur equation is : y = 0.85x + 5.25 or C(t) = 0.85t + 5.25 <==
cost of a 12 min taxi ride.....sub in 12 for t
C(t) = 0.85t + 5.25
C(12) = 0.85(12) +5.25
C(12) = 10.20 + 5.25 = 15.45
so a 12 min ride would cost u : $ 15.45 <==
Answer:
It is binomial:
p= 0.75 = 75%
1-p = 0.25 = 25%
N = 10
k=7
"seven successes in 10 trials"
(10 choose 7) (0.75)^7 ( 0.25)^3 =
(10*9*8 / 3*2) * (0.75)^7 ( 0.25)^3 =
(5*3*8) (0.75)^7 ( 0.25)^3
120 (0.75)^7 ( 0.25)^3
= 0.25028228759765625
or just over 25%
Step-by-step explanation:
Answer:
13.89% of students are willing to report cheating by other students.
Step-by-step explanation:
We are given the following in the question:
Sample size, n = 180
Number of students who reported cheating, x = 25
We have to find the proportion of the students are willing to report cheating by other students.
Proportion of students can be calculate as
Thus, 13.89% of students are willing to report cheating by other students.
Answer:
=19
Step-by-step explanation:
=6÷3+17
=2+17
=19
