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Trava [24]
3 years ago
15

Find the value of x in this figure

Mathematics
2 answers:
antoniya [11.8K]3 years ago
5 0
X^2 = 12^2 + 5^2
x^2 = 144 + 25
x^2 = 169
x = 13

hope it helps
melomori [17]3 years ago
3 0

Answer:

x = 13 units .

Step-by-step explanation:

Given  : A circle with tangent PQ , radius = 5 units , OQ = x .

To find : Find the value of x .

Solution : We have given circle with tangent PQ = 12, radius = 5 units , OQ = x .

The tangent (PQ) to a circle is perpendicular to the radius at the point of tangency ( P).

So, it formed the right triangle PQO.

Now use the Pythagorean Theorem :

(OQ)²  = ( PQ)² + (OP)².

Plug the values PQ = 12, OP =5 units , OQ = x .

(x)²  = ( 12)² + (5)².

(x)²  = 144 + 25 .

(x)²  = 169

By taking the square root .

x = 13 .

Therefore, x = 13 units .

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Differential cos^2x dy/dx =e^y-tanx​
gulaghasi [49]

Answer:

y=t−1+ce

−t

where t=tanx.

Given, cos

2

x

dx

dy

+y=tanx

⇒

dx

dy

+ysec

2

x=tanxsec

2

x ....(1)

Here P=sec

2

x⇒∫PdP=∫sec

2

xdx=tanx

∴I.F.=e

tanx

Multiplying (1) by I.F. we get

e

tanx

dx

dy

+e

tanx

ysec

2

x=e

tanx

tanxsec

2

x

Integrating both sides, we get

ye

tanx

=∫e

tanx

.tanxsec

2

xdx

Put tanx=t⇒sec

2

xdx=dt

∴ye

t

=∫te

t

dt=e

t

(t−1)+c

⇒y=t−1+ce

−t

where t=tanx

8 0
3 years ago
Gary drove to the park at a rate of 50 miles per hour if it took him 2.5 hours to get from his house to the park how far away is
Marina86 [1]

Answer:

The distance of the park from the Gary's house is 125 miles.

Step-by-step explanation:

Speed of Gary = 50 miles/hour

Time taken by Gary to reach the park from his house = 2.5 hours

Now, we know that,

Distance travelled = speed × time

So,  distance between park and Gary's house = speed × time

= 50 × 2.5

= 125 miles

So, the park is 125 miles away from the Gary's house.

4 0
3 years ago
Please help with this! Will give brainliest if the answer is right!
sweet-ann [11.9K]

Answer:


Step-by-step explanation:

Can u plz write it i cant see the pic


8 0
4 years ago
Help me with this... ​
marin [14]

i. 171

ii. 162

iii. 297

Solution,

n(U)= 630

n(I)= 333

n(T)= 168

i. Let n(I intersection T ) be X

333 - x + x + 468 - x = 630 \\ or \: 333 + 468 - x = 630 \\ or \: 801 - x = 630 \\ or \:  - x = 630 - 801 \\ or \:  - x =  - 171 \\ x = 171

<h3>ii.n(only I)= n(I) - n(I intersection T)</h3><h3> = 333 - 171</h3><h3> = 162</h3>

<h3>iii. n ( only T)= n( T) - n( I intersection T)</h3><h3> = 468 - 171</h3><h3> = 297</h3>

<h3>Venn- diagram is shown in the attached picture.</h3>

Hope this helps...

Good luck on your assignment...

4 0
4 years ago
Describe the transformations from the parent y=|x-2|+1 urgent pls answer.
Zanzabum

Answer:

find he domain by finding where the equation is defined. the range is the set of values that correspond with the domain.

8 0
3 years ago
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