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sasho [114]
3 years ago
5

Please help! - Kim needs to place 32 mystery books and 56 biography books on library shelves. She is to place the maximum number

of books on each shelf so that all the shelves have the same number of books. Each shelf will contain only one type of book. (Questions are in the picture, sorry for spelling mistakes)

Mathematics
2 answers:
Jet001 [13]3 years ago
5 0

Answer: Part A : the number of books to place o each shelf is 8 Part B :Kim would use 11 shelves  

Step-by-step explanation:


Oksi-84 [34.3K]3 years ago
3 0
A. 8 books on each shelf
B. 4 shelves for mystery, 7 shelves for biography
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A pie chart titled Which Pet Would you Choose: Dog, Cat, or Fish question mark. 50 percent chose a dog, 25 percent chose a cat,
Galina-37 [17]

Answer:

25%

Step-by-step explanation:

It says 25% chose fish.

5 0
3 years ago
There are 2 more angles. m angle 7 and m angle 8
Licemer1 [7]
ANSWER:

A and B aren't parallel lines, as the alternate angles aren't equivalent to each other.

For m angle 1 -

Vertically opposite angles are equivalent to each other.

m angle 1 is vertically opposite m angle 4.

Therefore:

m angle 4 = 100

m angle 1 = m angle 4

m angle 1 = 100

For m angle 6 -

Co-interior angles add up to 180°.

m angle 4 and m angle 6 are co-interior angles.

Therefore:

m angle 4 = 100

m angle 4 + m angle 6 = 180

100 + m angle 6 = 180

m angle 6 = 180 - 100

m angle 6 = 80

For m angle 7 -

Vertically opposite angles are equivalent to each other.

m angle 6 is vertically opposite m angle 7.

Therefore:

m angle 6 = 80

m angle 7 = m angle 6

m angle 7 = 80

For m angle 8 -

Corresponding angles are equivalent to each other.

m angle 8 and m angle 4 are corresponding angles.

Therefore:

m angle 4 = 100

m angle 8 = m angle 4

m angle 8 = 100

Hence, the angles are as follows:

m angle 1 = 100

m angle 6 = 80

m angle 7 = 80

m angle 8 = 100

Hope this helps! <3
5 0
3 years ago
Can u please help with problem 1. (ONLY IF YOU KNOW)
Flura [38]
Is the question number 2 you need help
3 0
3 years ago
Read 2 more answers
You have a six-sided die that you roll once. Let Ri denote the event that the roll is i. Let G j denote the event that the roll
Misha Larkins [42]

Answer:

a. P (R3 | G1)=\frac{1}{5}

b. P (R6| G3)= \frac{1}{3}

c. P(G3|E)=\frac{2}{3}

d. P (E|G3)=\frac{2}{3}

Step-by-step explanation:

The sample space associated with the random experiment of throwing a dice is is the equiprobable space {R1, R2, R3, R4, R5, R6}. Then,

a. The conditional probability that 3 is rolled given that the roll is greater than 1? P (R3 | G1) = \frac{P (R3\bigcap G1)}{P(G1)} = \frac{1/6}{5/6} = \frac{1}{5}

b. What is the conditional probability that 6 is rolled given that the roll is greater than 3? P (R6| G3) = \frac{P (R6\bigcap G3)}{P(G3)} = \frac{1/6}{3/6} = \frac{1}{3}

c. What is P [GIE], the conditional probability that the roll is greater than 3 given that the roll is even? P(G3|E) = \frac{P (G3\bigcap E)}{P(E)} = \frac{2/6}{3/6} = \frac{2}{3}

d. Given that the roll is greater than 3, what is the conditional probability that the roll is even? P (E|G3) = \frac{P (E\bigcap G3)}{P(G3)} = \frac{2/6}{3/6} = \frac{2}{3}

6 0
3 years ago
Evaluate the limit as h goes to 0 of (3+h)^4 -81/h
Montano1993 [528]

Answer:6

Step-by-step explanation:Take the derivative of the numerator and denominator, then evaluate the limit.

8 0
3 years ago
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